For every 33 green triangles, we have 77 yellow triangles.
So using the original ratio 33:77 we can simplify this by dividing both sides by 11 so that we get the ratio 3:7 so for every 3 green triangles we have 7 yellow triangles.
Draw or sketch out any problems like this, otherwise they appear abstract.
A circle’s area can be calculated by (pi d^2)/4 We have an area of 56 cm (^2?), so
pi d^2 = 56 x 4 (or 224) d^2 = 224/pi, d = √(224/pi)
A circle circumscribed around a square has a diameter equivalent to the length of the square’s diagonal, so the square’s diagonal is √(224/pi) (same as the circle diameter…)
A square’s side can be calculated, knowing its diagonal length, by use of Pythagoras’ theorem… The diagonal √(224/pi) is squared, divided by two, since the square’s sides are all equal, and the resulting number’s square root is calculated.
Squaring √(224/pi), we get 224/pi, and dividing by two, we get 112/pi, which is 35.6507 (cm^2), and the square root is 5.9708 cm, the side of the square.
I cannot emphasize enough that a drawing or sketch is an invaluable tool for these tasks, it saves having to retain a “picture” in your head. Note that a calculator was not required up until the last moment, dividing 112 by pi, and finding the square root of that answer. Picking up the calculator too early obliges you to transcribe numbers from the calculator to paper, and that can lead to issues. Try to enjoy maths, see it as a challenge not a chore. (and use correct units!)
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Related Questions (More Answers Below)
Answer:
-9 and +4 are the factors
Step-by-step explanation:
-9 times +4 is -36 and if you add +4 to -9, you get -5.
After this your function will look like this:
and then:
so the answer is:
No.
A chord is a straight segment that joins two points of the circumference. It starts at a point in the circumference and ends at other point in the circumference.
The radius goes from the center of the circle (which is not on the circumference) to one point of the circumference.
The diameter is a chord (the largest chord possible); but not the radius.
