<u>I'll assume you need to find the equation of the line that passes through those points.</u>
Answer:
Step-by-step explanation:
<u>Equation of a Line:</u>
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:
The given points are (-4,2) and (12,6), thus:
Operating:
Simplifying, the equation in point-slope form is:
<u>Given</u>:
The given circle with center at C. The lines AB and AD are tangents to the circle C.
The length of AB is (3x + 10)
The length of AD is (7x - 6)
We need to determine the value of x.
<u>Value of x:</u>
Since, we know the property of tangent that, "if two tangents from the same exterior point are tangent to a circle, then they are congruent".
We shall determine the value of x using the above property.
Thus, we have;
AB = AD
Substituting the values, we get;
Subtracting both sides of the equation by 7x, we get;
Subtracting both sides of the equation by 10, we get;
Dividing both sides of the equation by -4, we get;
Thus, the value of x is 4.