Answer:
Distance, S = 13m
Explanation:
Given the following data;
Initial velocity, u = 4m/s
Final velocity, v = 9m/s
Time, t = 2 seconds
To find the distance, S;
First of all, we would determine the acceleration of the shark.
Acceleration = (v - u)/t
Acceleration = (9 - 4)/2
Acceleration = 5/2
Acceleration = 2.5m/s²
Now, to find the distance we would use the second equation of motion
S = ut + ½at²
Substituting into the equation, we have
S = 4(2) + ½*2.5*2²
S = 8 + 1.25*4
S = 8 + 5
Distance, S = 13m
Answer:
8.64 x 10^7 J
Explanation:
Intensity of sunlight, I = 1000 W/m^2
Length of panel, L = 6 m
Width of panel, W = 4 m
Area of the panel, A = L x W = 6 x 4 = 24 m^2
time, t = 1 hour = 3600 second
Energy = Intensity x area of panel x time
E = 1000 x 24 x 3600 = 8.64 x 10^7 J
Answer:
D
Explanation:
The particles will move side to side over large areas
(a) We will use the equation v = u + at
Initial velocity u = 5.00 m/s
Acceleration a = 0.0600 m/s²
time = 8 min = 8 x 60 = 480 s
Final velocity
= u + at
= 5.00 + 0.0600(480)
= 33.8 m/s
The final velocity is 33.8 m/s
Answer:
θ = cos^(-1) (-A/B)
Explanation:
The image of the reauktant forces A & B are missing, so i have attached it.
Now, from the attached image, we will see that;
Angle between A and B is θ
Also;
A = Bcos(180° − θ)
Now, in trigonometry, we know that;
cos(180° − θ) = -cosθ
Thus;
A = -Bcosθ
cosθ = -A/B
Thus;
θ = cos^(-1) (-A/B)
