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Ostrovityanka [42]
3 years ago
9

According to the text, why is the choice not to attend

Physics
2 answers:
iogann1982 [59]3 years ago
7 0

Answer:

The answer is B. Without a college education, workers will actually lose money in the long run.

Explanation:

Just got it right on the assignment

zepelin [54]3 years ago
4 0

Answer:

B

Explanation:

cause I say so and you are desperate enough to cheat

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An organism's scientific name consists of...
Finger [1]

Answer:

binomial nomenclature.

Explanation:

This means that an organism's scientific name is a combination of two terms.

The first is the name of the organism's genus, and the second is the name of the organism's species

together the genus and the species create the name of a single organism.

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3 years ago
Which of the following can break solid rock
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I would think the answer would be c

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According to most car mechanics, plain water is the best coolant to use in an engine provided the engine is not being exposed to
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Ethylene glycol reduces the cooling efficiency of water because it has a lower heat capacity as compared to water. A substance with low heat capacity would mean that the material only needs a small amount of energy to increase its temperature. So, for ethylene glycol, the heat transfer would be faster decreasing the cooling efficiency.
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What is the sum of all forces acting on an object and direction
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3 0
3 years ago
A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/
s344n2d4d5 [400]

Answer:

At t = (70 / 3) \; {\rm s} (approximately 23.3 \; {\rm s}.)

Explanation:

Note that the acceleration of the car between t = 0\; {\rm s} and t = 20\; {\rm s} (\Delta t = 20\; {\rm s}) is constant. Initial velocity of the car was v_{0} = 0\; {\rm m\cdot s^{-1}}, whereas v_{1} = 35\; {\rm m\cdot s^{-1}} at t = 20\; {\rm s}\!. Hence, at t = 20\; {\rm s}\!\!, this car would have travelled a distance of:

\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}.

At t = 20\; {\rm s}, the truck would have travelled a distance of x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}.

In other words, at t = 20\; {\rm s}, the truck was 400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m} ahead of the car. The velocity of the car is greater than that of the truck by 35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}. It would take another (50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s} before the car catches up with the truck.

Hence, the car would catch up with the truck at t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}.

3 0
2 years ago
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