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rodikova [14]
4 years ago
13

A magnetic field applies forces on:a)static chargesb)moving chargesc)water flow​

Physics
2 answers:
lisabon 2012 [21]4 years ago
4 0

Answer:

moving charges b)

I think this is the answer

konstantin123 [22]4 years ago
3 0

Answer:

It is moving charges.

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Good science does not depend on interactions within the scientific community true or false
vlabodo [156]

Answer:

I would say that is false. Science can only be perfect after at least some sort of scientific communication and interaction.

6 0
3 years ago
Label the sound wave-   amplitude, wavelength,  crest, trough​
enot [183]

Answer:

A - Crest,  B - amplitude,  C - wavelength,  D - trough

Explanation:

7 0
3 years ago
You travel 85 miles in 2 hours, you then travel 75 miles in 1.5 hours. After a 0.5 hour rest break you then travel 55 miles in 1
Lera25 [3.4K]
Total 215 miles in 5 hours .hope it helps
8 0
4 years ago
Un objeto que es empujado sobre una superficie plana, tiene una masa de 80 kg y dicha fuerza tiene un valor de 300 N. Calcule la
Gennadij [26K]

Responder:

A. Ff = 300 N N = 784,8 N

Explicación:

Dado

Masa del cuerpo = 80 kg

Fuerza de movimiento Fm = 300N

Dado que el cuerpo no está acelerando, la fuerza de fricción (Ff) es igual a la fuerza de movimiento que actúa sobre el cuerpo, ya que la fuerza de fricción es una fuerza de oposición, es decir, Fm = Ff

Dado que Fm = 300N, Ff = 300N

La reacción normal que actúa en el cuerpo es igual al peso.

N = W = mg

g es la aceleración debida a la gravedad

g = 9,8 m / s

N = mg

N = 80 (9,81)

N = 784,8N

Por tanto, la fuerza normal que actúa sobre el cuerpo es 784,8 N

3 0
3 years ago
A flea jumps by exerting a force of 1.07 10-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground
Aleonysh [2.5K]

Answer:

a) 15.77 m/sec2

b) 13.3 deg

Explanation:

we are given;

Flea force = F1=1.07×10⁻5 N j

Breeze force = F2 = 1.14× 10⁻6 N (-j

mass of flea =6.0 ×10⁻7 kg

So net force on the flea=F1+F2+weight of flea=1.07×10⁻5 j +1.14× 10⁻6 i + 6.0 ×10⁻7 (-j) ×9.8= ma

==> ma = 1.07×10⁻5 j - 0.588×10⁻5 j + 0.114×10⁻5 i

==> ma= 0.482 ×10⁻5 j +0.114×10⁻5 i

==> ma = 0.114×10⁻5 i +0.482 ×10⁻5 j

== a = (0.114×10⁻5 i +0.482 ×10⁻5 j) / 6.0 ×10⁻7

==> a =

==>a= (1.9 j+8.03 i ) m/sec2

mag of a \sqrt{1.9^{2}  +8.03^{2} = 15.77 m/sec2

direction angle = tan⁻1(1.9/8.03)=13.3°

8 0
3 years ago
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