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Blababa [14]
3 years ago
5

If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th

e path difference?
Physics
2 answers:
Karolina [17]3 years ago
7 0
The path difference between two waves is the distance between the two waves. This distance may be obtained as the product of the order of the maxiuma or minima and the wavelength of the wave. The formula is:
d*sin∅ = nλ

Substituting the values for the distance between slits and the angle:
nλ = 0.05 * sin(0.25)
nλ = 2.18 x 10⁻⁴ m

The path difference is 0.2 millimeters.
blsea [12.9K]3 years ago
7 0

It should be 2200 nm and for the second part "How many orders of bright lines does this equal for red light with a wavelength of 650 nm?" it should be 3 wavelengths.

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The basic building blocks of matter is the -----
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<span>The basic building blocks of matter is the atom.</span>
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according to newton's first law of motion what is the reason for a ball throwing up in the airfall back to earth
skelet666 [1.2K]
The force of earth's gravitational field is always directed downwards (towards the center of the earth. When the ball is thrown up, it is going against the earth's gravitational field and so, the earth's gravitational force pulls it back down, accelerating it downwards.
5 0
3 years ago
Two subway stops are separated by 1210 m. If a subway train accelerates at 1.30 m/s2 from rest through the first half of the dis
solong [7]

Answer:

Part 1) Time of travel equals 61 seconds

Part 2) Maximum speed equals 39.66 m/s.

Explanation:

The final speed of the train when it completes half of it's journey is given by third equation of kinematics as

v^{2}=u^2+2as

where

'v' is the final speed

'u' is initial speed

'a' is acceleration of the body

's' is the distance covered

Applying the given values we get

v^2=0+2\times 1.30\times \frac{1210}{2}\\\\v^{2}=1573\\\\\therefore v=39.66m/s

Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as

v=u+at\\\\v=0+1.30\times t\\\\\therefore t=\frac{39.66}{1.30}=30.51seconds

Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance

Thus total time of journey equalsT=2\times 30.51\approx61seconds

Part b)

the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals 39.66m/s

4 0
4 years ago
A person of weight 600 n is standing with one foot on each of two bathroom scales. The scales readings are?
kakasveta [241]

The scales readings are 300 N for each of the scale.

<h3>What is weight?</h3>

The weight of an object is the force acting on the object due to gravity.

Weight is a vector quantity because it varies from place to place due to difference in acceleration due to gravity and it is measured in Newton (N).

<h3>Reading of each scale</h3>

The total weight of the person is supported by the two legs and if the person stand on a level ground, the weight will be evenly distributed and each scale will carry half of the person's weight.

The reading of each scale due to the weight of the person is calculated as follows;

Reading of each scale = total weight / 2

Reading of each scale  = 600 N/2

Reading of each scale  = 300 N

Thus, the scales readings are 300 N for each of the scale.

Learn more about weight here: brainly.com/question/2337612

#SPJ1

6 0
2 years ago
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