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Blababa [14]
3 years ago
5

If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th

e path difference?
Physics
2 answers:
Karolina [17]3 years ago
7 0
The path difference between two waves is the distance between the two waves. This distance may be obtained as the product of the order of the maxiuma or minima and the wavelength of the wave. The formula is:
d*sin∅ = nλ

Substituting the values for the distance between slits and the angle:
nλ = 0.05 * sin(0.25)
nλ = 2.18 x 10⁻⁴ m

The path difference is 0.2 millimeters.
blsea [12.9K]3 years ago
7 0

It should be 2200 nm and for the second part "How many orders of bright lines does this equal for red light with a wavelength of 650 nm?" it should be 3 wavelengths.

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Identify equivalent terms for stored energy and energy of motion.
Luba_88 [7]

Answer:

a. Stored energy is potential energy, and energy of motion is kinetic energy

Explanation:

The correct option is - a. Stored energy is potential energy, and energy of motion is kinetic energy.

Reason -

Potential energy is stored energy, whereas kinetic energy is the energy of moving things.

  • Kinetic energy is energy possessed by an object in motion.
  • The energy associated with position is called potential energy .
7 0
3 years ago
The equation that is used to solve second law problems is # F= ma.
maw [93]
F= Force 
M=Mass
A= acceleration 
F=N 
Mass= in grams or kilo grams (mostly kg)
A= m/s 

8 0
3 years ago
A hydrogen atom is in its ground state when its orbital electron:
Harlamova29_29 [7]
It is in its ground state when its orbital electron is at its lowest energy amount. 
8 0
3 years ago
A wind turbine is rotating at 15 rpm under steady winds flowing through the turbine at a rate of 42,000 kg/s. The tip velocity o
zzz [600]

Answer:

a) 5.22 m/s

b) 31.4 %

Explanation:

f = rotating speed = 15 rpm = 15/60 =0.25 rps

m = Mass flow rate of air = 42000 kg/s

v = Tip velocity = 250 km/h = 250/3.6 = 69.44 m/s

W = Work output = 180 kW

A = Swept area of wind turbine

r = Radius of wind turbine

η = Efficiency

r=\frac{v}{2\pi f}\\\Rightarrow r=\frac{250\div 3.6}{2\pi 0.25}=\frac{250}{1.8\pi}

A=\pi r^2\\\Rightarrow A=\pi\left(\frac{250}{1.8\pi}\right)^2\\\Rightarrow A=\left(\frac{250}{1.8}\right)^2\frac{1}{\pi}

m=\rho V\\\Rightarrow m=\rho vA\\\Rightarrow v=\frac{m}{\rho A}\\\Rightarrow v=\frac{42000}{1.31 \left(\frac{250}{1.8}\right)^2\frac{1}{\pi}}\\\Rightarrow v=5.22\ m/s

∴ The average velocity of the air is 5.22 m/s

E=m\frac{v^2}{2}=42000\frac{5.22^2}{2}\\\Rightarrow E=572538.92

\eta=\frac{W}{E}=\frac{180000}{572538.92}\\\Rightarrow \eta =0.314

∴ Conversion efficiency of the turbine is 0.314 or 31.4 %

7 0
3 years ago
Read 2 more answers
A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with
Ray Of Light [21]

Answer:

See below

Explanation:

Vertical position = 45 +  20 sin (30) t  - 4.9 t^2

 when it hits ground this = 0

               0 = -4.9t^2 + 20 sin (30 ) t + 45

                0 = -4.9t^2 + 10 t +45 = 0     solve for t =4.22 sec

  max height is at  t= - b/2a = 10/9.8 =1.02

     use this value of 't' in the equation to calculate max height = 50.1 m

      it has  4.22 - 1.02 to free fall = 3.2 seconds free fall

           v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL

      it will <u>also</u> still have horizontal velocity =  20 cos 30 = 17.32 m/s

        total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30  * t  =  20 *  cos 30  * 4.22 = 73.1 m

8 0
2 years ago
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