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Blababa [14]
3 years ago
5

If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th

e path difference?
Physics
2 answers:
Karolina [17]3 years ago
7 0
The path difference between two waves is the distance between the two waves. This distance may be obtained as the product of the order of the maxiuma or minima and the wavelength of the wave. The formula is:
d*sin∅ = nλ

Substituting the values for the distance between slits and the angle:
nλ = 0.05 * sin(0.25)
nλ = 2.18 x 10⁻⁴ m

The path difference is 0.2 millimeters.
blsea [12.9K]3 years ago
7 0

It should be 2200 nm and for the second part "How many orders of bright lines does this equal for red light with a wavelength of 650 nm?" it should be 3 wavelengths.

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alicia measured the mass of 23.00 ml of water. it was 22.9320 g. what is likely to be the temperature of the water?
Neporo4naja [7]

The concept of density allows finding that for the measured data the water temperature is 25ºC

Given parameters

  • The mass m = 22.9320 gr ( \frac{1 kg}{1000g} ) = 22.9320 10⁻³ kg
  • The volume V = 23.00 cm³ (\frac{1m}{10^{2}cm} )³ = 23.00 10⁻⁶ m³

To find

  • Temperature

Density is defined by the relationship between the mass of a body and its density, it is a very useful concept.

            \rho = \frac{m}{V}

Where ρ is the density, m the mass, and V the volume of the body.

Mass is a constant that depends on the amount of matter in a substance, therefore it does not depend on its temperature.

The volume of a body depends on the distance between the atoms or molecules that has some kind of dependence with the energy that unites them, therefore, as it has more energy (higher temperature), the volume must increase.

Let's calculate the density with of the water

         \rho = \frac{22.9320 \ 10^{-3} }{ 23.00 \ 10^{-6}}

         ρ = 997.0 kg / m³

Water is a material where the dependence of density with temperature is tabulated, in the table we can see some values ​​of interest

Temperature (ºC)     Density (kg / m³)

       0.01                         999.8

       4                            1000

      10                             999.7

     20                             998.3

     25                             997.1

     30                             995.7

When reviewing the table we see that the water temperature for this density must be T = 25ºC

Using the concept of density we can find that the temperature of the water is 25ºC

Learn more about density here:

brainly.com/question/24699260

3 0
3 years ago
A person in a kayak starts paddling, and it accelerates from 0 to 0.65 m/s in a distance of 0.40 m. If the combined mass of the
SCORPION-xisa [38]

Answer:

Magnitude of the net force acting on the kayak = 39.61 N

Explanation:

Considering motion of kayak:-

Initial velocity, u =  0 m/s

Distance , s = 0.40 m

Final velocity, v = 0.65 m/s

We have equation of motion v² = u² + 2as

Substituting

   v² = u² + 2as

    0.65² = 0² + 2 x a x 0.4

    a = 0.53 m/s²

We have force, F  = ma

Mass, m = 75 kg

    F  = ma = 75 x 0.53 = 39.61 N

Magnitude of the net force acting on the kayak = 39.61 N

6 0
4 years ago
Consider the following electron configurations to answer the question:
Anika [276]

Answer:

(ii) 1s2 2s2 2p6 3s2

Explanation:

Electron Affinity is the energy change that occur when an atom gains an electron.

                                  X₍₉₎ + e⁻  →  X⁻           ΔE = E<em>ea</em>

ΔE is change in energy

E<em>ea is electron affinity</em>

Often, electron affinity has negative energy values. The more negative the electron affinity, the easier it is to add an electron to a particular atom. Electron affinity increases across the period in the periodic table. However, there are few exceptions:

1. The electron affinities of group 18 (8A) elements are greater than zero. This is because the atom has a filled valence shell, an addition of electron causes the electron to move to a higher energy shell.

2. The electron affinities of group 2 (2A) elements are more positive because addition of an electron requires it to reside in the previously unoccupied p sub-shell.

3. The electron affinities of group 15 (5A) elements are more positive because addition of an electron requires it to be put in an already occupied orbital.

Applying these consideration to the elements given in the question:

(i) The sum of the electron in 1s²2s² 2p⁶ 3s¹ = 2+2+6+1 = 11 Sodium (Na)

(ii) The sum of the electron in 1s² 2s² 2p⁶ 3s² = 2+2+6+2 = 12 Magnesium (Mg)

(iii) The sum of the electron in 1s² 2s² 2p⁶ 3s² 3p¹ = 2+2+6+2+1 = 13 Aluminium (Al)

(iv) The sum of the electron in 1s² 2s² 2p⁶ 3s² 3p⁴ = 2+2+6+2+4 = 16 Sulfur (S)

(v) The sum of the electron in 1s² 2s² 2p⁶ 3s² 3p⁵ = 2+2+6+2+5 = 17 Chlorine (Cl)

The atom that is expected to have a positive electron affinity is Magnesium which is a group 2A element with electron configuration of 1s² 2s² 2p⁶ 3s².

4 0
4 years ago
(a) Calculate the distance that light travels in 0.5 seconds, and express the answer in units of the circumference of the earth.
Elan Coil [88]

Answer:

a)  3.74 circumference of earth

b)1.67× 10⁻⁸ sec

Explanation:

a) given,

time =  0.5 second

distance = speed  × time

              = 3 x 10⁸ × 0.5  

              = 1.5 × 10⁸ m

circumference of earth = 40075 km

                                       = 4.01 × 10⁷m

distance with respect to circumference=\dfrac{1.5 \times 10^8}{4.01 \times 10^7}

                                                                 = 3.74 circumference of earth

b) distance = 5 m

time =\dfrac{distance}{speed}

        =\dfrac{5}{3\times 10^8}

        = 1.67× 10⁻⁸ sec

6 0
3 years ago
A special triangular frame is being made for a piece of artwork. The the base of the triangular frame must be 90 cm. If the area
Mashutka [201]

Answer:

Explanation:

base of triangular frame, b = 90 cm

Area, A = 765 cm²

Let the height is h.

Area of a triangular frame = 1/2 x base x height

765 = 0.5 x 90 x h

h = 17 cm

Thus, the height of triangular frame is 17 cm.

5 0
3 years ago
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