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Nataly [62]
3 years ago
9

Organic Chem help please!

Chemistry
1 answer:
Yanka [14]3 years ago
3 0
Organic chemistry is a chemistry subdiscipline involving the scientific study of the structure, properties, and reactions of organic compounds and organic materials, i.e., matter in its various forms that contain carbon atoms. Study of structure includes many physical and chemical methods to determine the chemical composition and the chemical constitution of organic compounds and materials.
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How many silver atoms are there in 3.78g of silver?
oksian1 [2.3K]

2.1 x 10²²atoms

Explanation:

Given parameters:

Mass of silver = 3.78g

Unknown:

Number of atoms of silver = ?

Solution:

To solve this problem, we first find the number of moles of the silver from the given mass.

  Number of moles = \frac{Mass}{Molar mass}

Molar mass of Ag  = 108g/mole

   Number of moles = \frac{3.78}{108}  = 0.035mole

Now;

  A mole of any substance contains 6.02 x 10²³ atoms

     0.035 moles of Ag will contain 0.035 x 6.02 x 10²³ = 2.1 x 10²²atoms

learn more:

Number of moles  brainly.com/question/13064292

#learnwithBrainly

8 0
3 years ago
A backpacker collects snow at 0°C, and places it in a cooking pot on a camp stove. It takes 643 kJ of heat energy to melt the sn
frutty [35]

Answer:

mass (m) of the snow that the backpacker collected= 0.855 kg

Explanation:

Given that:

Q = 643 kJ = 643000 J

ΔHfusion = 6.02 kJ/mol = 6020 J/mol

number of mole of water H2O = \frac{mass (m)}{18}

c = 4.18 J/g⋅K

ΔT = 100 K

Since there is a phase change from solid to liquid; then :

Q = Q_s + Q_l

ΔH = \frac{q}{mol}

However without the given mass; we substitute \frac{m}{18} for the number of moles; so:

Q = \delta H * \frac{m}{18} + m*c * \delta T

643000 =6020 * \frac{m}{18}+ m * 4.18 * 100

m = 855 g

m = 0.855 kg

mass (m) of the snow that the backpacker collected= 0.855 kg

8 0
3 years ago
Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0
klemol [59]

Answer:

Partial pressure of methane: 1.18 atm

Partial pressure of ethane: 1.45 atm

Partial pressure of propane: 2.35 atm

Explanation:

Let the total moles of gases in a container be n.

Total pressure of the gases in a container =P = 5.0 atm

Temperature of the gases in a container =T = 23°C = 296.15 K

Volume of the container = V = 10.0 L

PV=nRT (Ideal gas equation)

n=\frac{PV}{RT}=\frac{5.0 atm\times 10.0 L}{0.0821 atm L/mol K\times 296.15 K}=2.0564 mol

Moles of methane gas =n_1=\frac{8.00 g}{16.04 g/mol}=0.4878 mol

Moles of ethane gas =n_2=\frac{18.00 g}{30.07 g/mol}=0.5986 mol

Moles of propane gas =n_3=?

n=n_1+n_2+n_3

n_3=n-n_1-n_2=2.0564 mol-0.4878 mol-0.5986 mol= 0.9700 mol

Partial pressure of all the gases can be calculated by using Raoult's law:

p_i=P\times \chi_i

p_i = partial pressure of 'i' component.

\chi_1 = mole fraction of 'i' component in mixture

P = total pressure of the mixture

Partial pressure of methane:

p_1=P\times \chi_1=P\times \frac{n_1}{n_1+n+2+n_3}=P\times \frac{n_1}{n}

p_1=5.00 atm\times \frac{0.4878 mol}{2.0564 mol}=1.18 atm

Partial pressure of ethane:

p_2=P\times \chi_2=P\times \frac{n_2}{n_1+n+2+n_3}=P\times \frac{n_2}{n}

p_2=5.00 atm\times \frac{0.5986 mol}{2.0564 mol}=1.45 atm

Partial pressure of propane:

p_3=P\times \chi_3=P\times \frac{n_3}{n_1+n+2+n_3}=P\times \frac{n_3}{n}

p_3=5.00 atm\times \frac{0.9700 mol}{2.0564 mol}=2.35 atm

5 0
4 years ago
True and false. if false explain
Sonja [21]

Answer:

The boiling point of water, or any liquid, varies according to the surrounding atmospheric pressure. ... With that much less pressure, you don't need to apply as much heat to push vapor pressure beyond the surrounding atmospheric pressure – in other words, water boils at a lower temperature.

4 0
3 years ago
The expected product from the addition of HCl to CH3â€"CH2â€"CH=CH2 is
Rudiy27

Answer:CH3â€"CH2â€"CHClâ€"CH3

Explanation:

This is due to Makownikov's rule which states that the negative part of the addendum adds to the carbon atom with the least numberbif hydrogen atoms. Another explanation is that, this product is formed from a secondary carbocation which makes it thermodynamically more stable. Compared to the minor product formed from a primary carbocation.

3 0
4 years ago
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