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ira [324]
3 years ago
10

A fan blade rotates with angular velocity given by ωz(t)= γ − β t2, where γ = 5.20 rad/s and β = 0.810 rad/s3 . calculate the an

gular acceleration as a function of time t in terms of β and γ.
Chemistry
1 answer:
Gnesinka [82]3 years ago
5 0

Answer : The angular acceleration is \alpha=-\beta t=-0.810\text{ t}

Solution : Given,

\gamma=5.20rad/s

\beta=0.810rad/s^3

The given angular velocity equation is,

\omega_z(t)=\gamma-\beta t^2

At t = 0,    \omega_z(0)=\gamma

At t = t,      \omega_z(t)=\gamma-\beta t^2

Angular acceleration : It is defined as the rate of change of angular velocity with respect to time.

Formula used for angular acceleration :

\alpha=\frac{\omega_z(t)-\omega_z(0)}{t}

where,

\alpha = angular acceleration

\omega_z(t) = angular velocity at time 't'

\omega_z(0) = angular velocity at time '0'

t = time

Now put all the given values in this formula, we get the angular acceleration.

\alpha=\frac{(\gamma)-(\gamma-\beta t^2)}{t}

\alpha=-\beta t=-0.810\text{ t}

Therefore, the angular acceleration is \alpha=-\beta t=-0.810\text{ t}

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Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

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The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

as

1 mole of NaHCO3 produces 1 mole of NaCl

Therefore,

molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g

molar mass of NaCl = 23 + 35.5 = 58.5 g

1 mole of NaHCO3 = 84 g

1 mole of NaCl  = 58.5 g

since 84 g of NaHCO3 produces 58.5 g of NaCl

10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

Theoretical yield of NaCl = (10 × 58.5)/84

Theoretical yield of NaCl = 585/84

Theoretical yield of NaCl  = 6.9642857143 g

percentage yield of NaCl = actual yield/theoretical yield × 100

percentage yield of NaCl = 6.73/6.9642857143 × 100

percentage yield of NaCl = 673/6.9642857143

percentage yield of NaCl = 96.635897436%

percentage yield of NaCl = 96.64%

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A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an
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<u>Answer:</u> The value of K_c for the reaction at 550.3 K is 247.83

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

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