DF congruent to AC and EF is common side
Answer:
Step-by-step explanation:
the perimeter P=2(L+W)=54
P=2L+2W=54 OR L+W=27
we know that L=3W+3
P=3W+W=27-3
4W=24
W=6 CM
L=21CM
Answer with explanation:
In Δ ABC and ΔD BC
∠A=∠D-------Given
∠ABC=∠DCB-------Each being 90° given in the Diagram.
Side, BC is Common.
⇒⇒Δ ABC ≅ ΔD BC-------[AAS]
When two triangles are congruent , their areas are equal.
So, Area(ABC)=Area (DCB)
Option B :⇒ A AS
Answer:
Step-by-step explanation:
<-- Given
<-- Distributive Property
<-- Find LCD of x-terms
<-- Combine Like Terms
<-- Add 45/8 to both sides
<-- Simplify Right Side
<-- Subtract 7 on both sides
<-- Divide both sides by 289/60
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