use cross products
(3r+6) *2 = 9*(2r-4)
6r+12 = 18r-36 distribute
12 = 12 r -36 subtract 6r from each side
48 = 12r add 36 to each side
4=r divide by 12
Answer:
The minimum score required for an A grade is 88.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the minimum score required for an A grade.
Top 12%, which is at least the 100-12 = 88th percentile, which is the value of X when Z has a pvalue of 0.88. So it is X when Z = 1.175.




Rounding to the nearest whole number
The minimum score required for an A grade is 88.
Answer: 1.66375e+13
Step-by-step explanation:
Answer:
The tree is thirty feet tall (30)
Step-by-step explanation:
So you divide 6 by 15 and you get .4
Then you multiply .4 by 75
And then you have 30
which the answer is 30