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bazaltina [42]
3 years ago
12

Eat at Joe's! Did you know that this neon sign is experiencing a change of state? When a neon sign lights up, like the one you s

ee here, something is happening to the neon atoms inside the tube. How is this colorful sign related to kinetic energy and phase change? A) The electrical current in the tube generates the neon gas that glows in the dark. B) Electrical energy excites the neon atoms. They spin faster in the tube producing electromagnetic waves that we see as colors. C) Neon atoms accelerate once electrical energy is turned on to the tube. The faster the atoms move in the tube, the brighter the glow we see. D) Electrical energy accelerates the electrons in the neon gas. The gas ionizes and becomes plasma, containing both positive and negative ions.
Chemistry
2 answers:
vlabodo [156]3 years ago
5 0
D) <span> Electrical energy accelerates the electrons in the neon gas. The gas ionizes and becomes plasma, containing both positive and negative ions.</span>
kykrilka [37]3 years ago
3 0
The answer is D. E<span>lectrical energy accelerates the electrons in the neon gas. The gas ionizes and becomes plasma, containing both positive and negative ions. </span>
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Thermal energy always moves from a greater energy level to a lesser energy level
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\fbox{Law -Based \: on \: laws \: of \: thermodynamic}

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6 0
2 years ago
A concentration cell consisting of two hydrogen electrodes (PH2 = 1 atm), where the cathode is a standard hydrogen electrode and
Lunna [17]

The pH of the unknown solution is 3.07.

<u>Explanation:</u>

<u>1.Find the cell potential as a function of pH</u>

From the Nernst Equation:

Ecell=E∘cell−RT /zF × lnQ

where

R denotes the Universal Gas Constant

T denotes the temperature

z denotes the moles of electrons transferred per mole of hydrogen

F denotes the Faraday constant

Q denotes the reaction quotient

Substitute the values,

E∘cell=0   lnQ=2.303logQ

E0cell=−2.30/RT /zF × log Q

Solving the equation,

<u>2. Find the Q  value</u>

Q=[H+]2prod pH₂, product/ [H+]2reactpH₂, reactant

Q=[H+]^2×1/1×1=[H+]2

Taking the log

logQ= log[H+]^2=2log[H+]=-2pH

From the formula,

Ecell=−2.303RT /zF× logQ

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( inverse)

E cell= 0.0592 V × pH

<u>3. Finding the pH value</u>

E cell= 0.0592 V × pH

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pH=3.07

The pH of the unknown solution is 3.07.

7 0
3 years ago
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