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bazaltina [42]
3 years ago
12

Eat at Joe's! Did you know that this neon sign is experiencing a change of state? When a neon sign lights up, like the one you s

ee here, something is happening to the neon atoms inside the tube. How is this colorful sign related to kinetic energy and phase change? A) The electrical current in the tube generates the neon gas that glows in the dark. B) Electrical energy excites the neon atoms. They spin faster in the tube producing electromagnetic waves that we see as colors. C) Neon atoms accelerate once electrical energy is turned on to the tube. The faster the atoms move in the tube, the brighter the glow we see. D) Electrical energy accelerates the electrons in the neon gas. The gas ionizes and becomes plasma, containing both positive and negative ions.
Chemistry
2 answers:
vlabodo [156]3 years ago
5 0
D) <span> Electrical energy accelerates the electrons in the neon gas. The gas ionizes and becomes plasma, containing both positive and negative ions.</span>
kykrilka [37]3 years ago
3 0
The answer is D. E<span>lectrical energy accelerates the electrons in the neon gas. The gas ionizes and becomes plasma, containing both positive and negative ions. </span>
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Hydrogen gas has a density of 0.090 g/L, and at normal pressure and -1.72 C one mole of it takes up 22.4 L. How would you calcul
BlackZzzverrR [31]

Answer:

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Explanation:

Assuming that all caculations are at normal pressure and -1.72°C :

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Where

n is the number of moles of hydrogen

n is the mass of hydrogen

\rho is the density of hydrogen

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Fe (s) + Pb(NO3), (aq) —&gt; ___<br><br> Type of reaction: _____
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Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) + H2O (l) → Ca(OH)2 (s) In a p
dybincka [34]

Answer:

The option closest to the percentage yield is option;

d. 81.1

Explanation:

The given chemical equation of the reaction is presented as follows;

CaO (s) + H₂O (l) → Ca(OH)₂

The mass of CaO in the experiment, m = 2.00 g

The volume of water with which the CaO was reacted = Excess volume of water

Number of moles = Mass/(Molar mass)

The mass of Ca(OH)₂ recovered, actual yield = 2.14 g

The molar mass of CaO = 56.0774 g/mol

The number of moles of CaO in the reaction, n₁ = 2.00 g/(56.0774 g/mol ≈ 0.036 moles

The molar mass of Ca(OH)₂ = 74.093 g/mol

The number of moles of Ca(OH)₂ in the reaction, n₂ = 2.14 g/(74.093 g/mol) ≈ 0.029 moles

From the given chemical reaction, one mole of CaO reacts with one mole of H₂O to produce one mole of Ca(OH)₂

Therefore, 0.036 moles of CaO will produce 0.036 moles of Ca(OH)₂

Mass = Number of moles × Molar mass

The mass of 0.036 moles of Ca(OH)₂ ≈ 0.036 moles × 74.093 g/mol = 2.667348 grams

∴ The theoretical yield of Ca(OH)₂ = 2.667348 grams

Percentage \ yield = \dfrac{Actual \ yield}{Theoretical \ yield}  \times 100 \%

The percentage yield = (2.14 g)/(2.667348 grams) × 100 = 80.23%

Therefore, the option which is closest is option d. 81.1.

5 0
3 years ago
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