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2 years ago

What is the slope of the line that passes through the points (1,-1) and (3,-7)? Group of answer choices

Mathematics

1 answer:

strojnjashka [21]2 years ago

3 0

Answer:

C. -3

Step-by-step explanation:

Slope = (y2-y1 / x2-x1). -7 - -1 / 3 - 1 = -6 / 2 = -3

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Harlamova29_29 [7]

Profit (P) is calculated by subtracting the total cost (C) from the total revenue (R). The calculations are shown below,

R = (1440 dozens) x (12 pieces / 1 dozen) x (25 cents/ piece) = $4320
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Profit = R - C = $4320 - $3600 = $720

Thus, the businessman's profit is $720.

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2 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

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$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

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madam [21]

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