Answer:
v' = 1.5 m/s
Explanation:
given,
mass of the bullet, m = 10 g
initial speed of the bullet, v = 300 m/s
final speed of the bullet after collision, v' = 300/2 = 150 m/s
Mass of the block, M = 1 Kg
initial speed of the block, u = 0 m/s
velocity of the block after collision, u' = ?
using conservation of momentum
m v + Mu = m v' + M u'
0.01 x 300 + 0 = 0.01 x 150 + 1 x v'
v' = 0.01 x 150
v' = 1.5 m/s
Speed of the block after collision is equal to v' = 1.5 m/s
Answer:
1.8nA
Explanation:
I = dq/dt
I = 9.0 × 10 ^-12 / 0.5 × 10^-3
I = 1.8 × 10× 10^-8
I = 1.8nA
Projectile<span>: Object that moves horizontally or at an angle to the Earth's surface. parabolic: The shape of the </span>curved path<span> of a </span>projectile<span>. air resistance: A force of friction produced when an object moves through the air.
So essentially when the projectile moves the air resistance causes the projectile to follow the parabolic, or the curved path.</span>