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3 years ago

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A 1.1 kg ball drops vertically onto a floor, hitting with a speed of 23 m/s. It rebounds with an initial speed of 5.0 m/s. (a) W

hat impulse acts on the ball during the contact

1 answer:

e-lub [12.9K]3 years ago

4 0

Hi there!

We know that:

I = Δp = m(vf - vi)

Plug in the given values. Remember to take into account direction ⇒ let the rebound velocity be positive and initial be negative.

I = 1.1(5 - (-23)) = 30.8 Ns

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Explanation:

From the question we are told that

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where

Initial moment

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$m_1=8.7*10^-^2kg$

Final moment

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Work done by Piston movement pressure

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$W=20000J$

Heat function

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$h=402$

Therefore

$Q=(0.792*0.718(440)-0.0871*0.718(400)+20-(0.792-0.087)*402))$

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