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djverab [1.8K]
4 years ago
10

An fm radio station broadcasts at a frequency of 97 mhz . what inductance should be paired with a 7.0 pf capacitor to build a re

ceiver circuit for this station?
Physics
1 answer:
SIZIF [17.4K]4 years ago
8 0
<span>xL = xC </span>

<span>ωL = 1/ωC </span>

<span>L = 1/(ω²C) </span>

<span>L = 1/((2πf)²C) </span>

<span>L = 1/((2π * 91 E6)²(10 E-12)) </span>

<span>L = 3.059 E-7 H </span>
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A commercial jet liner takes off with an average acceleration of 3 g. How long does it take to reach the end of its runway which
ANEK [815]

Answer:

The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

Explanation:

Given;

average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²

distance traveled by the commercial Jet liner, s = 1542 m

The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;

s = ut + ¹/₂at²

where;

u is the initial velocity of the commercial Jet liner = 0

s = 0 + ¹/₂at²

s = ¹/₂at²

2s = at²

t = \sqrt{\frac{2s}{a} } \\\\t = \sqrt{\frac{2 \times 1524}{29.4} } \\\\t = 10.18 \ s

Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

6 0
3 years ago
What are some other examples of scientific knowledge that must have resulted from indirect evidence?
n200080 [17]

Answer:

The atomic model, the structure of the solar system, and the theory of black holes are examples of models created using indirect evidence.

Explanation:

I have no explanation sorry.

5 0
3 years ago
Describe the energy transformations that occur when you bounce a ball?
Gemiola [76]
The transformation is kinetic energy
7 0
4 years ago
Read 2 more answers
. Take a stick of length one and denote it by the unit interval [0, 1]. Pick two i.i.d. Uniform(0, 1) random variables U and V a
BartSMP [9]

Answer:

What is the expected value of L = 1/3

Explanation:

kindly check the attached file below.

5 0
4 years ago
Una cámara fotográfica analógica (no digital) tiene dos lentes intercambiables. Uno de foco 55mm y el otro de 200 mm. Toma una f
Sergeu [11.5K]

Answer:

f = 55mm,     h ’= -9.89 cm

f = 200 mm,  h ’= 42.5 cm

Explanation:

For this exercise let's start by finding the distance to the image, using the equation of the constructor

         \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distances to the object and image, respectively

lens with f₁ = 55mm = 0.55cm

         \frac{1}{q} = \frac{1}{f} - \frac{1}{p}

         \frac{1}{q_1} = \frac{1}{0.55} - \frac{1}{10}

          \frac{1}{q_1} = 1.718

          q₁ = 0.582 m

lens with f₂ = 200mm = 2m

           \frac{1}{q_2} =   \frac{1}{2} - \frac{1}{10}

            \frac{1}{q_2} = 0.4

            q₂ = 2.5 m

the magnification of a lens is given by

            m = \frac{h'}{h} = -  \frac{q}{p}

             h ’= - \frac{q}{p} \ h

let's calculate for each lens

f = 55mm

             h '= - 0.582 / 10 1.7

             h ’= 0.0989 m

             h ’= -9.89 cm

f = 200 mm

             h '= - 2.5 / 10 1.7

             h ’= -0.425 m

             h ’= 42.5 cm

The negative sign indicates that the image is real and inverted

4 0
3 years ago
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