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Crank
3 years ago
9

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELP!!!!!!!

Mathematics
2 answers:
svet-max [94.6K]3 years ago
7 0

Answer:

a = 2; \ d = 2; \ c=1; \ b=1

Step-by-step explanation:

Two functions are inverse where their composition results in a variable only:

f(g(x))=x

So, we have to insert the right numbers in place of letters a, b, c and d, to fulfil this definition. Those value would be: a = 2; \ d = 2; \ c=1; \ b=1

Replacing these values, we have:

f(x)=x+2

g(x)=1x-2=x-2

Applying the composition f(g(x)):

f(g(x))=\frac{cx-d+a}{b}

We observe that with this values, these functions are inverse, because it composition results <em>x.</em>

f(g(x))=\frac{1x-2+2}{1}=x

Therefore, the values are a = 2; \ d = 2; \ c=1; \ b=1

Alchen [17]3 years ago
3 0
F(x) = x + 1
          ------
            b

g(x) = cx - d


flip values of x and y in each equation, then solve for y:


x = y + a
      -------
         b

y = a - bx


``````````````````````````````````````````````````````````

x = cy - d

y = x + d
      -------
         c
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A

Step-by-step explanation:

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We know that the initial term <em>a</em> is 13, the common difference is 7, and the total sum is 2613. Since we want to find the number of terms, we want to find <em>n</em>.

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x_n=13+7(n-1)

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\displaystyle (2613)=\frac{n}{2}((13)+(13+7(n-1)))

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5226 = n (26+7n-7)

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7n^2+19n-5226=0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 7, <em>b</em> = 19, and <em>c</em> = -5226. Substitute:

\displaystyle x  =\frac{-(19)\pm\sqrt{(19)^2-4(7)(-5226)}}{2(7)}

Evaluate:

\displaystyle x = \frac{-19\pm\sqrt{146689}}{14} = \frac{-19\pm 383}{14}

Evaluate for each case:

\displaystyle x _ 1 = \frac{-19+383}{14} = 26\text{ or } x _ 2 = \frac{-19-383}{14}=-\frac{201}{7}

We can ignore the second solution since it is negative and non-natural.

Therefore, there are 26 terms in the arithmetic series.

Our answer is A.

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