Answer:
463833
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Medium
Solution
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In △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal
Hence, △ ABC is isosceles.
3+/-11
add 11 to 3
11+3=14
minus 11 from 3
3-11=-8
the coordinate could be 14 or -8
Answer:
f(-2) = 11
Step-by-step explanation:
Hello!
We can evaluate y by plugging in -2 for x in the equation.
<h3>Evaluate</h3>
- f(x) = 8|x| - 5
- f(-2) = 8|-2| - 5
- f(-2) = 8(2) - 5 Remember that absolute value turns the number positive
- f(-2) = 16 - 5
- f(-2) = 11
The evaluated value is 11.
Answer:
Putting the value of x of coordinate point (12,-2)
where x= 12
y= 5×12/6 -12
= 5(2)-12
=10-12 = -2
option D