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Lostsunrise [7]
3 years ago
8

Why does blowing carbon dioxide gas into aqueous barium hydroxide reduce?

Chemistry
2 answers:
siniylev [52]3 years ago
8 0

Barium hydroxide is soluble, which signifies that it will produce ions in the solution. Supplementing carbon dioxide will result in a precipitation reaction with Ba(OH)2, which is as follows:  

Ba(OH)₂ (aq) + CO₂ (g) → BaCO₃ (s) + H₂O (l)

As the ions are withdrawn from the solution, there is a reduction in the conductivity, due to this blowing carbon dioxide gas into aqueous barium hydroxide reduce.  

Oksana_A [137]3 years ago
5 0
<span>If one chooses to blow carbon dioxide gas into aqueous barium hydroxide it will reduce. This happens because the ions become removed from the solution and in turn this decreases the conductivity of it.</span>
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ludmilkaskok [199]

The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C

<h3>How to calculate temperature?</h3>

The initial temperature of the copper metal can be calculated using the following formula on calorimetry:

Q = mc∆T

mc∆T (water) = - mc∆T (metal)

Where;

  • m = mass
  • c = specific heat capacity
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According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

30,096 = 93.6T - 2246.4

93.6T = 32342.4

T = 345.5°C

Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.

Learn more about temperature at: brainly.com/question/15267055

8 0
1 year ago
A force of 100 newtons is applied to a box at an angle of 36º with the horizontal. If the mass of the box is 25 kilograms, what
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Answer:

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Based on the acting force that is applied horizontally, one can propose the following equation based on Newton's laws:

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Nevertheless, since we've got a angled force, it becomes:

F=macos\theta

In this case, cos\theta accounts for the formed angle, so the horizontal acceleration turns out into:

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