Barium hydroxide is soluble, which signifies that it will produce ions in the solution. Supplementing carbon dioxide will result in a precipitation reaction with Ba(OH)2, which is as follows:
Ba(OH)₂ (aq) + CO₂ (g) → BaCO₃ (s) + H₂O (l)
As the ions are withdrawn from the solution, there is a reduction in the conductivity, due to this blowing carbon dioxide gas into aqueous barium hydroxide reduce.
<span>If one chooses to blow carbon dioxide gas into aqueous barium hydroxide it will reduce. This happens because the ions become removed from the solution and in turn this decreases the conductivity of it.</span>
The density of CO2 getting from experiment is 0.1/0.056 = 1.79 g/L. The percent error of this is (1.96 -1.79)/1.96*100%=8.67%. So the approximate percent error is 8.67%.
