The question is incomplete, the complete question is :
Calculate the approximate number of atoms in a bacterium. Assume the average mass of an atom in the bacterium is 10 times the mass of a hydrogen atom.(Hint the mass of hydrogen atom is on order of 
kg and the mass of bacterium is on order of 
kg
Answer:
The total numbers of atom in bacterium are 
.
Explanation:
Mass of hydrogen atom, m= 
kg
Mass of bacterium , M= kg
Mass of bacterium atom =m'
Given ; 
let the number of atoms in bacterium be N
The total numbers of atom in bacterium are .
Answer:
1. 0.097 s
2. 0.420 M
Explanation:
To solve both questions we'll use the formula:
[A]ₓ = [A]₀ - kt
Where [A]ₓ is the concentration of A at a given time; and [A]₀ is the initial concentration.
1) We input the data given by the problem:
0.167 M = 0.700 M - 5.48 M/s * t
And solve for t:
t = 0.097 s
2) We input the new data:
[A]ₓ = 0.500 M - 0.361 M/s * 0.220 s
and solve for [A]ₓ:
[A]ₓ = 0.420 M
Answer:
= 97.44 Liters at S.T.P
Explanation:
The reaction between Iron (iii) oxide and Carbon monoxide is given by the equation;
Fe2O3(s)+ 3CO(g) → 3CO2(g) + 2Fe(s)
From the reaction when the reactants react, 2 moles of Fe and 3 moles of CO2 are produced.
Therefore; Mole ratio of Iron : Carbon dioxide is 2:3
Thus; Moles of Carbon dioxide = (2.9/2)×3
= 4.35 moles
But; 1 mole of CO2 at s.t.p occupies 22.4 liters
Therefore;
Mass of CO2 = 22.4 × 4.35 Moles
= 97.44 L
Answer:
Explanation:
The relative massive alpha particles could go through the gold foil without being deviated of their trajectory or only small deviations due to the uniformity distribution positive charge of the protons.
Quantitative data can be counted, measured, and expressed using numbers. Qualitative data is descriptive and conceptual.
