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sergij07 [2.7K]
2 years ago
5

How many cm is 0.375 ft.​

Chemistry
2 answers:
ivann1987 [24]2 years ago
8 0

Answer:

11.43 cm

Explanation:

frutty [35]2 years ago
5 0

Answer: 11.43

Explanation:

check for ur self

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Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
Katena32 [7]

Answer:

ΔH°r = -483.64 kJ

Explanation:

Let's consider the following balanced equation.

2 H₂(g) + O₂(g)  ⇒ 2 H₂O(g)

We can calculate the standard enthalpy change of the reaction (ΔH°r) using the following expression.

ΔH°r = ∑ΔH°f(p) × np - ∑ΔH°f(r) × nr

where

ΔH°f: standard heat of formation

n: moles

p: products

r: reactants

ΔH°r = ΔH°f(H₂O(g)) × 2 mol - ΔH°f(H₂(g)) × 2 mol - ΔH°f(O₂(g)) × 1 mol

ΔH°r = (-241.82 kJ/mol) × 2 mol - 0 kJ/mol × 2 mol - 0 kJ/mol × 1 mol

ΔH°r = -483.64 kJ

4 0
3 years ago
The lead pipe has a mass of 200 g, how much will be left after 6 months?
kumpel [21]

Answer:

33g

Explanation:

200 divided by 6=33.33

5 0
3 years ago
Give the value of the quantum number ℓ, if one exists, for a hydrogen atom whose orbital angular momentum has a magnitude of 6√(
MakcuM [25]

Answer:

For this angular momentum, no quantum number exist

Explanation:

From the question we are told that

   The magnitude of the angular momentum is  L  = 6\sqrt{\frac{h}{2 \pi} }

The generally formula for Orbital angular momentum is mathematically represented as

           L  = \sqrt{(l * (l + 1)) } *  \frac{h}{2 \pi}

Where l is the quantum number

now  

We can look at the given angular momentum in this form as

      L  = 6\sqrt{\frac{h}{2 \pi} }    =  \sqrt{36}  * \sqrt{\frac{h}{2 \pi}} }

comparing this equation to the generally equation for Orbital angular momentum

     We see that there is no quantum number that would satisfy this equation

5 0
3 years ago
Calculate the value of [CH3OH][CO][H2]2 when all concentrations are 2.4. Keep in mind that the reaction may not be at equilibriu
NikAS [45]

Explanation:

The given reaction will be as follows.

            CO + 2H_{2} \leftrightharpoons CH_{3}OH

So, equilibrium constant for this equation will be as follows.

              K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}

As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.

               K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}

                       = \frac{2.4}{2.4 \times (2.4)^{2}}

                       = 0.173

Thus, we can conclude that equilibrium constant for the given reaction is 0.173.  

3 0
3 years ago
Inside the room the air is often warmer near the ceiling than near the floor. Which of the following accounts for the difference
Rudiy27
The correct answer would be C. Convection, which describes that heat rises.
3 0
3 years ago
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