Given:
In triangle DEF, HG is parallel to DF.
To find:
The value of x.
Solution:
In triangles DEF and GEH,
(Common angle)
(Corresponding angle)
(By AA property of similarity)
We know that corresponding sides of similar triangle are proportional.





Isolating variable terms, we get



Therefore, the value of x is equal to 4.
Answer:
Step-by-step explanation:
a = 35 feet
b = 54 feet
h = 28 feet
![Area=\frac{[a+b]*h}{2}\\\\=\frac{[35+54]*28}{2}\\\\=\frac{89*28}{2}\\\\=89*14\\\\](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7B%5Ba%2Bb%5D%2Ah%7D%7B2%7D%5C%5C%5C%5C%3D%5Cfrac%7B%5B35%2B54%5D%2A28%7D%7B2%7D%5C%5C%5C%5C%3D%5Cfrac%7B89%2A28%7D%7B2%7D%5C%5C%5C%5C%3D89%2A14%5C%5C%5C%5C)
= 1246 square feet
The Answer is A. 5070π in3
Let X be the number of burglaries in a week. X follows Poisson distribution with mean of 1.9
We have to find the probability that in a randomly selected week the number of burglaries is at least three.
P(X ≥ 3 ) = P(X =3) + P(X=4) + P(X=5) + ........
= 1 - P(X < 3)
= 1 - [ P(X=2) + P(X=1) + P(X=0)]
The Poisson probability at X=k is given by
P(X=k) = 
Using this formula probability of X=2,1,0 with mean = 1.9 is
P(X=2) = 
P(X=2) = 
P(X=2) = 0.2698
P(X=1) = 
P(X=1) = 
P(X=1) = 0.2841
P(X=0) = 
P(X=0) = 
P(X=0) = 0.1495
The probability that at least three will become
P(X ≥ 3 ) = 1 - [ P(X=2) + P(X=1) + P(X=0)]
= 1 - [0.2698 + 0.2841 + 0.1495]
= 1 - 0.7034
P(X ≥ 3 ) = 0.2966
The probability that in a randomly selected week the number of burglaries is at least three is 0.2966