Answer:
Magnetic force,
Explanation:
It is given that,
Magnetic field, B = 2 T
Velocity of the proton, v = 300 m/s
Charge on the proton,
The magnetic field is oriented perpendicular to the proton’s velocity. The magnetic force on the charged particle is given by :
The magnetic field is oriented perpendicular to the proton’s velocity,
So, the magnitude of the force that the proton experiences while it moves through the magnetic field is . Hence, this is the required solution.
To solve this problem it is necessary to apply the concepts concerning the conservation of both potential and thermodynamic energy of the body. That is to say that as the body has a loss of potential energy it is gained in the form of thermal energy on water. If the potential energy is defined as
Where,
m= mass
g = Gravitational acceleration
h = Height
And thermal energy is obtained as
Where,
= Change in Temperature
Specific Heat
m = Mass
We can equate this equation and rearrange to find the change at the Temperature, then
Our values are given as,
Specific Heat Water
Using energy conservation
Replacing,
Therefore the temperature increase in a 1kg sample of water is 1.89K
Answer:
5 ) The mass, 6) with lubrication and using surfaces that are not rough
Explanation:
5) If two bodies are held regardless of their densities and can be combined by some chemical or physical process, the only physical property to be modified will be the mass of the resulting body.
8)
Friction depends on the contact between two surfaces and when a body has a relative motion with respect to a contact surface. In order to reduce friction the contact surface must be lubricated, also the friction depends on the coefficient of friction between surfaces and the normal force exerted by the surface parallel to the area of contact with the body. Mathematically it can be expressed with the following equation.
Answer:
700 mL or 0.0007 m³
Explanation:
P₁ = Initial pressure = 2 atm
V₁ = Initial volume = 350 mL
P₂ = Final pressure = 1 atm
V₂ = Final volume
Here the temperature remains constant. So, Boyle's law can be applied here.
P₁V₁ = P₂V₂
So, volume of this sample of gas at standard atmospheric pressure would be 700 mL or 0.0007 m³