Answer:
21.67 rad/s²
208.36538 N
Explanation:
= Final angular velocity =
= Initial angular velocity = 78 rad/s
= Angular acceleration
= Angle of rotation
t = Time taken
r = Radius = 0.13
I = Moment of inertia = 1.25 kgm²
From equation of rotational motion
The magnitude of the angular deceleration of the cylinder is 21.67 rad/s²
Torque is given by
Frictional force is given by
The magnitude of the force of friction applied by the brake shoe is 208.36538 N
A. 6,7000.56n is the correct choice according to siri lol