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lapo4ka [179]
3 years ago
10

Which of the following is NOT an example of a heating appliance?

Physics
1 answer:
tekilochka [14]3 years ago
5 0
Steam engine is not an example of a heating appliance
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A ball has a mass of 0.1 kg and an initial velocity of 20 m/s. The ball is given an acceleration of 30 m/s2 for 5 s. What is the
djverab [1.8K]

Answer:

acceleration = v-u /t

30- 20/5

= 10/5 = 2m/sec²

Force = mass * acceleration

Force = 0.1 * 2

Force = 0.2 Newton

6 0
3 years ago
Read 2 more answers
Find the direction and magnitude of Ftot, the total force exerted on her by the others, given that the magnitudes F1 and F2 are
Mars2501 [29]

Answer:

 θ = 36°

Explanation:

given,

F₁ = 22.8 N

F₂ = 16.6 N

magnitude of force = ?

direction of force = ?

F = \sqrt{F_1^2 + F_2^2}

F = \sqrt{22.8^2 + 16.6^2}

F = \sqrt{795.4}

      F = 28.20 N

direction

\theta = tan^{-1}(\dfrac{F_2}{F_1})

\theta = tan^{-1}(\dfrac{16.6}{22.8})

\theta = tan^{-1}(0.728)

       θ = 36°

5 0
3 years ago
A ball is thrown horizontally from the top of a building 37.5 m high. The ball strikes the ground at a point 80.3 m from the bas
trasher [3.6K]

Answer:

t = 2.77 s

Explanation:

The ball in its movement describes a curved line called a semiparabola, therefore two coordinates are required to fix the position at each instant of time, since the movement is performed in the X-Y plane:

Equation of movement of the ball in the X axis

X = v₀x*t   Equation  (1)

Equation of movement of the ball in the Y axis

Y = y₀+ v₀y*t -½ g*t² Equation  (2)

Where

X : horizontal position in meters (m)  

Y : vertical  position in meters (m)  

y₀ : initial vertical  position in meters (m)

v₀x :  X-initial speed in m/s  

v₀y :  Y-initial speed in m/s  

g: acceleration due to gravity in m/s²

t : time to position (X,Y)

Data

y₀ = 37.5 m

v₀y = 0

g = 9.8 m/s²

Problem development

The time the ball remains in the air is the same as the ball takes to touch the floor, that is, Y = 0

We apply the Equation (2):

Y = y₀+ (v₀y)*t - (½) g*t²

0 =  37.5 +(0)*t- (1/2)*(g)*t²

0 =  37.5 - (1/2)*(9.8)*t²

(1/2)*(9.8)*t²  = 37.5

t² = (2)(37.5)/(9.8)

t= \sqrt{\frac{2*37.5}{9.8} }

t = 2.77 s

5 0
3 years ago
An iron vat is 11 m long at room temperature (20°C). How much longer is it when it contains boiling water at 1 atm pressure?
RoseWind [281]

Answer:

The change in length is 0.01056 m.

Explanation:

Given that,

Length = 11 m

Temperature = 20°C

Pressure = 1 atm

Boiling temperature = 100°C

We need to calculate the length

Using formula of change in linear expansion

\dfrac{\Delta L}{L}=\alpha_{l}\Delta T

\Delta L=L\times\alpha_{l}\times(T_{f}-T_{i})

Put the value into the formula

\Delta L=11\times12\times10^{-6}\times(100-20)

\Delta L=11\times12\times10^{-6}\times80

\Delta L=0.01056\ m

Hence, The change in length is 0.01056 m.

5 0
3 years ago
Which of the following will result in learning violent behavior through observational learning?
vovikov84 [41]
What are the choices?

5 0
4 years ago
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