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3 years ago

As light shines from air to another medium, i = 42.0Â°. The light bends toward the normal and refracts at 38.0° What is

Physics

1 answer:

eduard3 years ago

8 0

Answer:

1.09

Explanation:

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During the course of a demonstration the professor is called away. When he returns he finds a beaker of water that was at room t

Yanka [14]

Answer:

Either heat added or mechanical work done.

Explanation:

Since he found stirring rod on the desk and a cigarette lighter. This means that the beaker was probably either heated with the aid of fire from the lighter.

Also, the stirring rod could have been used to stir the water which will increase the kinetic energy which also means an increase in temperature.

Thus, it's either heat was added or mechanical work was done as a result of stirring.

5 0

2 years ago

Please help on this one?

otez555 [7]

help me w mine and ill try to help with yours

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3 years ago

At the _______________ point, the particles in an object have not kinetic energy

Brums [2.3K]

The freezing point ..... :)

4 0

3 years ago

An MRI scanner is based on a solenoid magnet that produces a large magnetic field. The magnetic field doesn't stop at the soleno

GaryK [48]

Answer:

The maximum change in flux is $\Delta \o = 0.1404 \ Wb$

The average induced emf $\epsilon =0.11232 V$

Explanation:

From the question we are told that

The speed of the technician is $v = 0.80 m/s$

The distance from the scanner is $d = 1.0m$

The initial magnetic field is $B_i = 0T$

The final magnetic field is $B_f = 6.0T$

The diameter of the loop is $D = 19cm = \frac{19}{100} = 0.19 m$

The area of the loop is mathematically represented as

$A = \pi [\frac{D}{2} ]^2$

$= 3.142 \frac{0.19}{2}$

$= 0.02834 m^2$

At maximum the change in magnetic field is mathematically represented as

$\Delta \o = (B_f - B_i)A$

=> $\Delta \o = (6 -0)(0.02834)$

$\Delta \o = 0.1404 \ Wb$

The average induced emf is mathematically represented as

$\epsilon = \Delta \o v$

$= 0.1404 * 0.80$

$\epsilon =0.11232 V$

7 0

3 years ago

If a fish is trying to capture an insect hovering above the surface of the water – how will it jump to catch it? Will it aim abo

Viktor [21]

Answer:

It will have aim at a point "below" the insect.

From the insect's point of view, the fish will appear to be shallower than it actually is because a ray of light from the insect to the fish will be bent "towards" the normal when the ray enters the water

5 0

2 years ago