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kondaur [170]
3 years ago
6

Custom actions help your users by

Computers and Technology
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer:

D) Making it fast and easy to interact with information in your organization.

Explanation:

PLEASE MARK ME AS BRAINLIEST

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1D Array Assignment Outcome: Student will demonstrate the ability to use a one-dimensional array. Student will demonstrate the a
sukhopar [10]

Answer:

Program to this question as follows:

program:

import java.util.*; //import package for user input

public class Main  //defining class  

{

public static void main(String[] as)//defining main function

{//defining integer array

int [] num = new int[113];  

boolean find_in = false; //defining boolean variable

int [] counts = new int[101];//defining integer array

int y, tem = 0, counter = 0,in=0,x,find; //defining integer variable

Scanner ox= new Scanner(System.in); //creating Scanner class Object

while(counter <= 112) //loop to check condition

{

num[counter++] = generateRandomNumber(); //using array to hold random function value.  

}

System.out.println("The array:"); //message

for(x = 0; x < 112; x++) // loop to count the value

{

if(x != 0 && x % 9 == 0) // if block to chek value

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// sort in ascending order

Arrays.sort(num); //using sort method

System.out.print("\n\nThe array in sorted order:"); // print value

for( x = 0; x < num.length; x++) // loop uses if block to check value is divisiable by 9  

{

if(x % 9 == 0) //check condition  

System.out.println(); // print  

else

System.out.print(num[x] + " "); // print array

}

// search for a number

System.out.print("\n\nEnter a number to search: "); // print message

find= ox.nextInt(); // input number by user

for(x= 0;x< num.length;x++) //loop to count values

{

if(num[x] == find) //check value

{

find_in = true; //change value

in= x;

break; //using break keyword

}

}

if(find_in)  //find value

System.out.println(find + " is found at index " + in); // print location

else

System.out.println("Not found"); //message

// display count of each numbers

System.out.println("Count of each numbers:"); //message

for(y = 1; y< num.length; y++) // loop to store element in counts array  

{

tem = num[y]; //hold value

counts[tem]++; //increment value

}

for(x = 1; x< counts.length; x++) //loop to print value

{

System.out.println(x + ": " + counts[x]); // print value

}

// average of the numbers in the array

for(x = 0; x < num.length; x++) // loop to calculate sum and average

{

sum += num[x]; //calculate sum

}

avg = (sum / 100); // calculate avg

System.out.println("\nThe average of the numbers in the array: " + avg);

// highest number in the array

int high= num[0]; //find number

for(x= 0;x < num.length;x++)

{

if(num[x] > high)

high = num[x]; //hold value of highest Number

}

System.out.println("\nThe highest number is: " + high); //print value

int low = num[0]; // defining variable for lowest number

for(x= 0; x < num.length - 1; x++) // loop to calculate lowest number

{

if(num[x] < low) //condition for lowest number

low = num[x]; //hold lowest number

}

System.out.println("\nThe lowest number is: " + low); //print value

}

public static int generateRandomNumber() //defining function  

{

Random ra = new Random(); //creating Random function Object

return (ra.nextInt(100)+ 1); //input and return value

}

}

Output:

the output of the given code is display in image

Explanation:

In the above program, an array is declared that uses a random function to input the number, in the next step the sort function is used, that sorted all array elements, in the next step the scanner class is used, that input the number form the user ends and pass search in the sorted array.

  • After searching the average of array elements is calculated. In this array we calculate the highest and lowest number of the array to print all the values the print method is used.
  • At the last, the rand method is used that generates the random number for the array and passes into a num array that prints the values.

7 0
3 years ago
Fill in this function that takes three parameters, two Strings and an int. 4- // Write some test function calls here! The String
zimovet [89]

Answer:

The function in Java is as follows:

public static void printMessage(String lineOne, String lineTwo, int lines){

       for(int i = 1;i<=lines;i++){

           if(i%2 == 1){

               System.out.println(lineOne);

           }

           else{

               System.out.println(lineTwo);

           }

       }

   }

Explanation:

This defines the function

public static void printMessage(String lineOne, String lineTwo, int lines){

This iterates through the number of lines

       for(int i = 1;i<=lines;i++){

String lineOne is printed on odd lines i.e. 1,3,5....

      if(i%2 == 1){

               System.out.println(lineOne);

           }

String lineTwo is printed on even lines i.e. 2,4,6....

           else{

               System.out.println(lineTwo);

           }

       }

   }

To call the function from main, use:

printMessage("Hi", "Karel", 5);

8 0
2 years ago
Write about virus in five points.​
kvasek [131]
A computer virus is a malicious software program loaded onto a user's computer without the user's knowledge and performs malicious actions. It can self-replicate, inserting itself onto other programs or files, infecting them in the process.
5 0
2 years ago
Five advantages of Internet​
Novosadov [1.4K]

Answer:

Information, knowledge, and learning.

Selling and making money.

Banking, bills, and shopping.

Donations and funding

Entertainment.

Explanation:

I hope this helps! ^^

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7 0
2 years ago
Read 2 more answers
The OSI model is a useful tool in troubleshooting a network because it enables you to isolate a problem to a particular software
lutik1710 [3]

Answer:

1)  Layer 4, transport

2) Layer 2, datalink

3) Layer 5, session

4) Layer 7, application

Description of Problems are as below:

1) One of your servers has been exhibiting sluggish network performance. you use a network-monitoring program to try to evaluate the problem. You find considerable TCP retries occurring because the server is being overwhelmed by data, and packets are being discarded.

2) You check some statistics generated by a network-monitoring program and discovers that an abnormally high number of CRC errors were detected. (Hint think of the cause of CRC errors).

3) A user is trying to connect to another computer, but the logon attempt is continually rejected.

4) You try to access a Linux server to share files by using NFS. You can communicate with the server, but the shared files don't appear to be available.

Explanation:

OSI Model is a reference model to determine how applications communicate over a network. OSI consists of seven layers, and each layer performs a particular network function. The seven layers are:

   Layer 7 - Application.

   Layer 6 - Presentation.

   Layer 5 - Session.

   Layer 4 - Transport.

   Layer 3 - Network.

   Layer 2 - Data Link.

   Layer 1 - Physical.

1) One of your servers has been exhibiting sluggish network performance. you use a network-monitoring program to try to evaluate the problem. You find considerable TCP retries occurring because the server is being overwhelmed by data, and packets are being discarded.

Layer 4, transport

2) You check some statistics generated by a network-monitoring program and discovers that an abnormally high number of CRC errors were detected. (Hint think of the cause of CRC errors).

Layer 2, Data Link

3) A user is trying to connect to another computer, but the logon attempt is continually rejected.

Layer 5, session

4) You try to access a Linux server to share files by using NFS. You can communicate with the server, but the shared files don't appear to be available.

Layer 7, application

7 0
3 years ago
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