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Stels [109]
3 years ago
14

Not including four play in games, there are 64 teams in the tournament. once a team loses one game they are eliminated. how many

games would have been played if each team had to play every other team once?
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0
Every time teams play with each other (assuming there are no draws) half of them win
and the others get eliminated so
64÷2=32 32 games played and 32 teams eliminated
32÷2=16 16 games played and 16 teams eliminated
16÷2=8 the same goes here
8÷2=4 and here
4÷2=2 .
2÷2=1 .

32+16+8+4+2+1=63 games
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First, I'll make f(x) = sin(px) + cos(px) because this expression shows up quite a lot, and such a substitution makes life a bit easier for us.

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-----------------------------------

Let's compute dy/dx. We'll use f(x) as defined earlier.

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Use the chain rule here.

There's no need to plug in the expressions f(x) or f ' (x) as you'll see in the last section below.

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\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{dy}{dx}\right]\\\\\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{f'(x)}{f(x)}\right]\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-f'(x)*f'(x)}{(f(x))^2}\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2}\\\\

If you need a refresher on the quotient rule, then

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-----------------------------------

This then means

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Note the cancellation of -(f ' (x))^2 with (f ' (x))^2

------------------------------------

Let's then replace f '' (x) with -p^2*f(x)

This allows us to form  ( f(x) )^2 in the numerator to cancel out with the denominator.

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Side note: This is an example of showing that the given y function is a solution to the given second order linear differential equation.

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Answer:

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