Question

Not including four play in games, there are 64 teams in the tournament. once a team loses one game they are eliminated. how many games would have been played if each team had to play every other team once?

Answer 1

Every time teams play with each other (assuming there are no draws) half of them win
and the others get eliminated so
64÷2=32 32 games played and 32 teams eliminated
32÷2=16 16 games played and 16 teams eliminated
16÷2=8 the same goes here
8÷2=4 and here
4÷2=2 .
2÷2=1 .

32+16+8+4+2+1=63 games