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3 years ago

Question 8 (1 point)

Chemistry

2 answers:

Maslowich3 years ago

8 0

Answer:

1) 3 2) 2 3) 1 4) 3

Explanation:

so on the reactant side (left), there is 2 H, 1 CO3, and 1 Fe. On the product side (right) there is 2 Fe, 3 CO3, and 2 H2. So to start I added a 3 in the first blank to make CO3 equal on both sides. In doing this, there is not 2 H, there is now 6 so I added a 3 in the 4th blank. Currently, H and CO3 are equal on both sides but not Fe. So I added a 2 in the 2nd blank. I didn't add anything in the 3rd blank so it is an understood 1.

vladimir1956 [14]3 years ago

4 0

The balanced equation

3H₂CO₃ + 2Fe → Fe₂(CO₃)₃ + 3H₂

<h3>Further explanation</h3>

Given

Reaction

H₂CO₃ + Fe → Fe₂(CO₃)₃ + H₂

Required

Coefficient of the reaction

Solution

Give a coefficient(the most complex = 1)

aH₂CO₃ + bFe → Fe₂(CO₃)₃ + cH₂

Make an equation

Prioritize balancing the elements that form the most complex compounds

Fe, left = b, right = 2⇒b=2

C, left = a, right = 3⇒a=3

H, left = 2a, right = 2c⇒2a=2c⇒2.3=2c⇒6=2c⇒c=3

The equation becomes :

3H₂CO₃ + 2Fe → Fe₂(CO₃)₃ + 3H₂

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Zigmanuir [339]

Answer:

Stock solution = 1.25 *10^-3 M

Dilution 1 = 5*10^-4 M

Dilution 2= 3.75 * 10^-4 M

Dilution 3 = 2.5 *10^-4 M

Dilution 4 = 1.25 *10^-4 M

Explanation:

Step 1: Data given

The stock solution is made by diluting 5.00 ml of 1.250 x 10-2 M salicylic acid in 50.00 mL of solution.

Step 2: Calculate the concentration of the stock solution:

M1*V1 = M2*V2

⇒ with M1 = the initial concentration = 1.250 *10^-2 M

⇒ with V1 = 5 mL = 5*10^-3 L

⇒ with M2 = TO BE DETERMINED

⇒ with V2 = 50 mL = 50 *10^-3 L

M2 = (M1*V1)/V2

M2 = (1.250 *10^-2 * 5*10^-3 L) / 50 *10^-3

M2 = 0.00125 M = 1.25 *10^-3 M

Step 3: Calculate dilution 1

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 *10^-3)/(25*10^-3L)

M2 = 0.0005 M = 5*10^-4 M

Step 4: Calculate dilution 2

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 * 7.5*10^-3)/(25*10^-3)

M2 = 0.000375 M = 3.75 * 10^-4 M

Step 5: Calculate dilution 3

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 5*10^-3) /(25*10^-3)

M2 = 0.00025 M = 2.5 *10^-4 M

Step 6: Calculate dilution 4

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 2.5*10^-3)/(25*10^-3)

M2 = 0.000125 M = 1.25 *10^-4 M

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3 years ago

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sergij07 [2.7K]

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Answer:

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3 years ago

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3 years ago

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Answer:

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