Answer:
The molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.HOW TO CALCULATE MOLARITY:The molarity of a solution can be calculated by dividing the number of moles by its volume. That is;Molarity = no. of moles ÷ volumeAccording to this question, 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide. The molarity is calculated as follows:Molarity = 0.50mol ÷ 2LMolarity = 0.25MTherefore, the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.Learn more about molarity at: brainly.com/question/2817451
Explanation:
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Answer:
Decreasing temperature.
Explanation:
- Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
- The choices here:
1) Decreasing concentration of SO₂,
The concentration of SO₂ decreases, so the reaction will be shifted to the left direction to suppress the decrease in SO₂ concentration.
2) Decreasing temperature,
ΔH= – 98.8 kJ/mol, the negative sign means that the reaction is exothermic and release the heat.
If the temperature decreased, this means that the products decrease, so the reaction will shift to the right to suppress the decrease in temperature.
<em>It is the right choice.</em>
3) Increasing concentration of SO₃:
Increasing concentration of SO₃ will shift the reaction to the left to suppress the effect of increasing the concentration of SO₃.
4) Increasing volume:
Increasing the volume will decrease the pressure.
Decreasing the pressure will shift the reaction of gases to the side of higher no. of moles (left side).
- <em>So, the right choice is: Decreasing temperature.</em>
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Answer: 2116.8 seconds
Explanation:
0.0035 weeks × 7days/week × 24hrs/day × 60min/hr × 60sec/min
=2116.8 seconds
=2100 (if you are required to consider significant figures)
<u>Answer:</u> The pH of the cleaning compound is 10.44
<u>Explanation:</u>
pH is defined as the negative logarithm of hydrogen or hydronium ion concentration that are present in a solution.
The equation representing pH of the solution follows:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
![[H^+]=3.6\times 10^{-11}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D3.6%5Ctimes%2010%5E%7B-11%7D)
Putting values in above equation, we get:


Hence, the pH of the cleaning compound is 10.44