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3 years ago

Question 8 (1 point)

Chemistry

2 answers:

Maslowich3 years ago

8 0

Answer:

1) 3 2) 2 3) 1 4) 3

Explanation:

so on the reactant side (left), there is 2 H, 1 CO3, and 1 Fe. On the product side (right) there is 2 Fe, 3 CO3, and 2 H2. So to start I added a 3 in the first blank to make CO3 equal on both sides. In doing this, there is not 2 H, there is now 6 so I added a 3 in the 4th blank. Currently, H and CO3 are equal on both sides but not Fe. So I added a 2 in the 2nd blank. I didn't add anything in the 3rd blank so it is an understood 1.

vladimir1956 [14]3 years ago

4 0

The balanced equation

3H₂CO₃ + 2Fe → Fe₂(CO₃)₃ + 3H₂

<h3>Further explanation</h3>

Given

Reaction

H₂CO₃ + Fe → Fe₂(CO₃)₃ + H₂

Required

Coefficient of the reaction

Solution

Give a coefficient(the most complex = 1)

aH₂CO₃ + bFe → Fe₂(CO₃)₃ + cH₂

Make an equation

Prioritize balancing the elements that form the most complex compounds

Fe, left = b, right = 2⇒b=2

C, left = a, right = 3⇒a=3

H, left = 2a, right = 2c⇒2a=2c⇒2.3=2c⇒6=2c⇒c=3

The equation becomes :

3H₂CO₃ + 2Fe → Fe₂(CO₃)₃ + 3H₂

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what is the molarity of liters of an aqueous solution that contains 0.50 mole of potassium iodide, KI

Marizza181 [45]

Answer:

The molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.HOW TO CALCULATE MOLARITY:The molarity of a solution can be calculated by dividing the number of moles by its volume. That is;Molarity = no. of moles ÷ volumeAccording to this question, 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide. The molarity is calculated as follows:Molarity = 0.50mol ÷ 2LMolarity = 0.25MTherefore, the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.Learn more about molarity at: brainly.com/question/2817451

Explanation:

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2 years ago

What stress will shift the following equilibrium system to the right? 2SO2(g) + O2(g) ⇌ 2SO3(g); ΔH= –98.8 kJ/mol Decreasing con

denpristay [2]

Answer:

Decreasing temperature.

Explanation:

Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
The choices here:

1) Decreasing concentration of SO₂,

The concentration of SO₂ decreases, so the reaction will be shifted to the left direction to suppress the decrease in SO₂ concentration.

2) Decreasing temperature,

ΔH= – 98.8 kJ/mol, the negative sign means that the reaction is exothermic and release the heat.

If the temperature decreased, this means that the products decrease, so the reaction will shift to the right to suppress the decrease in temperature.

It is the right choice.

3) Increasing concentration of SO₃:

Increasing concentration of SO₃ will shift the reaction to the left to suppress the effect of increasing the concentration of SO₃.

4) Increasing volume:

Increasing the volume will decrease the pressure.

Decreasing the pressure will shift the reaction of gases to the side of higher no. of moles (left side).

So, the right choice is: Decreasing temperature.

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4 years ago

Please help will give points Match the type of thermal energy with the letters on the drawing

Katen [24]

A: radiation

B: convection

C: conduction

7 0

3 years ago

Convert 0.0035 weeks into seconds.

Vesnalui [34]

Answer: 2116.8 seconds

Explanation:

0.0035 weeks × 7days/week × 24hrs/day × 60min/hr × 60sec/min

=2116.8 seconds

=2100 (if you are required to consider significant figures)

7 0

3 years ago

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The hydrogen ion concentration, [H+], in a certain cleaning compound is left bracket Upper H Superscript plus Baseline right

labwork [276]

Answer: The pH of the cleaning compound is 10.44

Explanation:

pH is defined as the negative logarithm of hydrogen or hydronium ion concentration that are present in a solution.

The equation representing pH of the solution follows:

$pH=-\log[H^+]$

We are given:

$[H^+]=3.6\times 10^{-11}$

Putting values in above equation, we get:

$pH=-\log(3.6\times 10^{-11})$

$pH=10.44$

Hence, the pH of the cleaning compound is 10.44

8 0

3 years ago