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Svetlanka [38]
3 years ago
13

it is 12 degrees colder in the mountains than in the valley. The temperature on the mountain is x. The temperature in the valley

is y
Mathematics
1 answer:
Grace [21]3 years ago
6 0
X= y+12

OR

Valley(y)= mountain(x)-12
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Among all right circular cones with a slant height of 24​, what are the dimensions​ (radius and​ height) that maximize the volum
aleksklad [387]

Answer:

5571.99

Step-by-step explanation:

We need to use the Pythagorean theorem to solve the problem.

The theorem indicates that,

r^2+h^2=24^2 \\r^2+h^2=576\\r^2=576-h^2

Once this is defined, we proceed to define the volume of a cone,

v=\frac{1}{3}\pi r^2 h

Substituting,

v=\frac{1}{3} \pi (576-h^2)h\\v=\frac{1}{3} \pi (576h-h^3)

We need to find the maximum height, so we proceed to calculate h, by means of its derivative and equalizing 0,

\frac{dv}{dh} = \frac{1}{3} \pi (576-3h^2)

\frac{dv}{dh} = 0 then \rightarrow \frac{1}{3}\pi(576-3h^2)=0

h_1=-8\sqrt{3}\\h_2=8\sqrt{3}

<em>We select the positiv value.</em>

We have then,

r^2 = 576-(8\sqrt3)^2 = 384\\r=\sqrt{384}

We can now calculate the maximum volume,

V_{max}= \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (\sqrt{384})^2 (8\sqrt{3}) = 5571.99

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3 years ago
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Find [h(x) +m(x)]-[h(x)-m(x)]<br> H(x)=1/3x3/3 3x2+9x-2<br> M(x)=13 3/5x+6x3-2x2-4x
Andre45 [30]

Answer:

\frac{276}{5}-8x)

Step-by-step explanation:

We are given with

H(x)=1/3x3/3 3x2+9x-2

And

M(x)=13 3/5x+6x3-2x2-4x

And asked to determine

[h(x) +m(x)]-[h(x)-m(x)]

Opening the second parenthesis

h(x) +m(x)-h(x)+m(x)

As we subtracted the second bracket, the sign get reversed.

As h(x) has opposite signs , they get cancelled

h(x) +m(x)-h(x)+m(x)

=2m(x)

=2(13\tfrac{3}/{5}x+6x3-2x2-4x)

=2(\frac{13 \times 5 + 3}{5}+18-4-4x)

=2(\frac{68}{5}+14-4x)

=2(\frac{68+70}{5}-4x)

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