Answer:
The square root of six hundred and eighty-three √683 = 26.13426869074
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The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
Check the original problem. If it's different from that which you have shared, share the correct version and come back here for further help.
<h2>
Answer:</h2>
Figure B
<h2>
Step-by-step explanation:</h2>
The Pythagorean Theorem is 
, where c is the longest side of the triangle (the hypotenuse).
To find the side length of each square, you have to square root the area of each square. This means that Figure A has side lengths of 3, 6 and 8 units. Figure B has side lengths of 5, 12 and 13 units.
In Figure A, if the triangle is right-angled, the equation 
must be correct. 9 + 36 = 45. 45 is not equal to 64, so the triangle is not right-angled.
In Figure B, if the triangle is right-angled, the equation 
must be correct. 25 + 144 = 169. 169 is 13 squared, so the triangle is right-angled.
Alternatively, as you are already given the square values for each side length, there is no need to square root and square again. You can just test if the two smaller areas equal the larger area, but the explanation above uses a more detailed example of the Pythagorean Theorem.
1. 3p: Add 6 to negative 3, and carry over the "p"
3. 6x: Subtract 1 from 7 and carry over the "x"
5. -4v: Add 6 to negative 10 and carry over the "v"
7. -4r + 9: Add 5 to -9 and carry over the "r". Then put "+9" after the variable, since the other 9 was by itself.
9. 14n: Add 5 to 9 and carry over the "n".
I hope this helps!
