<u>Answer:</u>
<u>For a:</u> The concentration of sodium and nitrate ions are 0.25 M and 0.25 M respectively.
<u>For b:</u> The concentration of magnesium and sulfate ions are and respectively.
<u>For c:</u> The concentration of glucose solution is 0.0150 M
<u>For d:</u> The concentration of sodium, chloride, ammonium and carbonate ions in the mixture are 0.111 M, 0.111 M, 0.0146 M and 0.0146 M respectively.
<u>Explanation:</u>
- <u>For a:</u> 0.25 M
The chemical equation for the ionization of sodium nitrate follows:
1 mole of sodium nitrate produces 1 mole of sodium ions and 1 mole of nitrate ions
Concentration of sodium ions = 0.25 M
Concentration of nitrate ions = 0.25 M
Hence, the concentration of sodium and nitrate ions are 0.25 M and 0.25 M respectively.
- <u>For b:</u> of
The chemical equation for the ionization of magnesium sulfate follows:
1 mole of magnesium sulfate produces 1 mole of magnesium ions and 1 mole of sulfate ions
Concentration of magnesium ions =
Concentration of sulfate ions =
Hence, the concentration of magnesium and sulfate ions are and respectively.
- <u>For c:</u> 0.0150 M
The given compound is a covalent compound and will not dissociate into its respective ions. So, the only chemical species present in the solution is
Hence, the concentration of glucose solution is 0.0150 M
- <u>For d:</u> A mixture of 45.0 mL of 0.272 M NaCl and 65.0 mL of 0.0247 M
To calculate the number of moles for given molarity, we use the equation:
.....(1)
<u>For sodium chloirde:</u>
Molarity of NaCl solution = 0.272 M
Volume of solution = 45.0 mL
Putting values in equation 1, we get:
<u>For ammonium carbonate:</u>
Molarity of ammonium carbonate solution = 0.0247 M
Volume of solution = 65.0 mL
Putting values in equation 1, we get:
Total volume of the solution = 45 + 65 = 110 mL
Molarity of NaCl in the mixture =
Molarity of ammonium carbonate in the mixture =
The chemical equation for the ionization of sodium chloride follows:
1 mole of sodium chloride produces 1 mole of sodium ions and 1 mole of chloride ions
Concentration of sodium ions = 0.111 M
Concentration of chloride ions = 0.111 M
The chemical equation for the ionization of ammonium carbonate follows:
1 mole of ammonium carbonate produces 1 mole of ammonium ions and 1 mole of carbonate ions
Concentration of ammonium ions = 0.0146 M
Concentration of carbonate ions = 0.0146 M
Hence, the concentration of sodium, chloride, ammonium and carbonate ions in the mixture are 0.111 M, 0.111 M, 0.0146 M and 0.0146 M respectively.