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My name is Ann [436]
3 years ago
6

Rn-222 has a half-life of 3.82 days. If 25.0 g of Radon-22 was originally present, approximately how many grams would be left af

ter 15 days?
Chemistry
1 answer:
horsena [70]3 years ago
6 0

Answer:

Approximately 0.39 g or 0.4 g if you're rounding up

Explanation:

15/3.82 = 3.92

Let's round that up to 4

That means 15 days is around 4 half lives

4 half lives means 1/16 of the original mass will be left

25/16 = 0.390625

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In addition to not causing damage to the sample, what is another advantage of using a microspectrophotometer to analyze fibers?
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Another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

<h3>What is a microspectrophotometer?</h3>

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Microspectrophotometry can also measure the emission of light by a sample, which is usually small as the micro implies.

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However, another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

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The decomposition of nitrogen dioxide is described by the following chemical equation: Suppose a two-step mechanism is proposed
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<u>first step </u>

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<u>second step</u>

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Explanation:

<u>first step </u>

NO2(g)  ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

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