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My name is Ann [436]
4 years ago
6

Rn-222 has a half-life of 3.82 days. If 25.0 g of Radon-22 was originally present, approximately how many grams would be left af

ter 15 days?
Chemistry
1 answer:
horsena [70]4 years ago
6 0

Answer:

Approximately 0.39 g or 0.4 g if you're rounding up

Explanation:

15/3.82 = 3.92

Let's round that up to 4

That means 15 days is around 4 half lives

4 half lives means 1/16 of the original mass will be left

25/16 = 0.390625

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nlexa [21]

Answer:

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Explanation:

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3 years ago
On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 25
Taya2010 [7]

The new volume of the bag : 747.43 ml

<h3>Further explanation</h3>

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

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\tt V_2=\dfrac{V_1.T_2}{T_1}\\\\V_2=\dfrac{250\times 873}{292}\\\\V_2=747.43~ml

7 0
3 years ago
An oxide of phosphorus contains 56.4% phosphorus and 43.6% oxygen. It's relative molecular mass is 220. Find both the empirical
sladkih [1.3K]
Moles of P = 56,4g/30,974g/mole = 1,82 moles P
moles of O = 43,6/15,999 = 2,73 moles of O

converting to the simplest ratio:
For P : 1,82/1,82 = 1
For O : 2,73/1,82 = 1,5

1 P and 2 oxygens.
PO2 -> the empirical formula

hope this help
7 0
3 years ago
Read 2 more answers
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soldier1979 [14.2K]

Answer:

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Explanation:

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4 years ago
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