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Illusion [34]
3 years ago
9

We explored the copper cycle. In the first step, copper was oxidized by nitric acid to make a green solution. Water was then add

ed to the solution and the color changed from green to blue. Is this result supported by the spectrochemical series?
Chemistry
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

Yes, the reaction is supported by spectrochemical series.

Explanation:

When copper oxidizes with concentrated nitric acid, it produces copper ions; and the nitric acid is then reduced to nitrogen dioxide, a very poisonous gas which is brown in color and with an irritating odor.

$ Cu + 4HNO_{3} \rightarrow Cu(NO_{3})_{2} + 2NO_2+2H_2O$

The copper ions ($Cu^{2+} $) product which is initially coordinated to form nitrate ions from nitric acid and thus first gives the solution a green color.

Now when the solution is further diluted with water, the water molecules then displaces the nitrate ions  around the copper ions and causes the solution to change its color to blue. The reaction is -

$ 3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2+ 2NO + 4H_2O $

Yes, the results are supported by spectrochemical series.

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What geological process(es) could form magnesium silicate perovskite at 500 C?
dimulka [17.4K]

Magnesium silicate is a compound of magnesium oxide and silicon. It is the magnesium salt of silicic acid containing an unspecified amount of water. The molecular formula can be expressed more clearly as MgSiO3.

7 0
2 years ago
The following reaction shows the products when sulfuric acid and aluminum hydroxide react.
Elden [556K]

The correct answer is approximately 11.73 grams of sulfuric acid.

The theoretical yield of water from Al(OH)3 is lower than that of H₂SO₄. As a consequence, Al(OH)3 is the limiting reactant, H₂SO₄ is in excess.

The balanced equation is:

2Al(OH)₃ + 3H₂SO₄ ⇒ Al₂(SO₄)₃ + 6H₂O

Each mole of Al(OH)3 corresponds to 3/2 moles of H₂SO₄. The molecular mass of Al(OH)3 is 78.003 g/mol. There are 15/78.003 = 0.19230 moles of Al(OH)3 in the five grams of Al(OH)3 available. Al(OH)3 is in limiting, which means that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.

The molar mass of H₂SO₄ is 98.706 g/mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.706 = 28.289 g

40 grams of sulfuric acid is available, out of which 28.289 grams is consumed. The remaining 40-28.289 = 11.711 g is in excess, which is closest to the first option, that is, 11.73 grams of H₂SO₄.

6 0
3 years ago
In the reaction below how would adding more of product C affect the equilibrium of the system? A+B arrows both ways C+D
Shalnov [3]

Answer:

1. The reaction will proceed backward, shifting the equilibrium position to the left.

2. The reaction will proceed forward, shifting the equilibrium position to the right.

3. Either add more of the products ( H2O or Cl2) or remove the reactant (HCl or O2)

Explanation:

3 0
3 years ago
Decide whether the compound is ionic or molecular, if you can.
mestny [16]

Answer:

Molecular solid

Explanation:

A molecular solid has a low melting point, they are soft and do not conduct electricity.

We have been told in the question that the solid does not really dissolve in water and it's solution does not improve the electrical conductivity of water. Hence, it must be a molecular solid.

7 0
3 years ago
Please answer the question
Tom [10]

Answer:

Stamens

Explanation:

7 0
3 years ago
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