Answer:
The worth of the car after 6 years is £2,134.82
Step-by-step explanation:
The amount at which Dan buys the car, PV = £2200
The rate at which the car depreciates, r = -0.5%
The car's worth, 'FV', in 6 years is given as follows;

Where;
r = The depreciation rate (negative) = -0.5%
FV = The future value of the asset
PV = The present value pf the asset = £2200
n = The number of years (depreciating) = 6
By plugging in the values, we get;

The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))
4 2/11 = 4.1818181
sqrt5 = 2.2360679......
3/16 = 0.1875
answer:
3/16 terminates ( it only has 4 numbers)
4 2/11 don't terminate but keeps repeating
sqrt5 doesn't terminate or repeat
Answer:
- 4.2 degrees
Step-by-step explanation:
If the drop was from temp 0 at 8 pm to temp -16.8 at midnight (4 hours later)
then,the drop is given by the rate: -16.8/4 = - 4.2 degrees per hour
Therefore, at 9 pm the temperature was:
0 degrees - 4.2 degrees = - 4.2 degrees
Answer:
a
=
4/
1
−
|
x
|
h
=
0
Step-by-step explanation:
It could be any fraction from 5/9 to 7/9.