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Alisiya [41]
3 years ago
5

Consider the following exothermic reaction and predict how the change below will affect the concentration (increase, decrease, s

tay the same) of each component in the system as the equilibrium is reestablished.
3N2H4 (g) â 4NH3 (g) + N2 (g)

N2 H2 NH3
Add N2(g)
Remove 112(g)
Add NH3(g)
Add Ar(g)
Increase the temperature (constant P)
Decrease the volume (constant T)
Add a catalyst
Chemistry
1 answer:
aev [14]3 years ago
3 0

Answer:

a) equilibrium shifts towards the left

b) equilibrium shifts towards the right hand side.

c)equilibrium shifts towards the left hand side

d) addition of argon has no effect on the equilibrium position

e) equilibrium position shifts towards the left hand side

f) equilibrium position is shifted towards the right hand side

g) addition of a catalyst has no effect on the equilibrium position

Explanation:

Given the equation;

3N2H4(g)⇄ 4NH3 (g) + N2 (g)

Adding N2

The addition of N2 will increase the concentration of N2 in the system thereby shifting the equilibrium position to the left in accordance with Le Chatelier's principle.

Removing N2

The removal of N2 drives the forward reaction and the equilibrium shifts towards the right yielding more N2 in accordance with Le Chateliers principle.

Add NH3

The addition of NH3 will shift the equilibrium position towards the left hand side according to Le Chateliers principle.

d) addition of argon has no effect on the equilibrium position.

e) increasing the temperature

Since the reaction is exothermic, increasing the temperature favours the reverse reaction and the equilibrium position his shifted towards the left hand side.

f) Decrease in volume;

Decreasing the volume favours the forward reaction hence the equilibrium position is shifted towards the right.

g) addition of a catalyst has no effect on the equilibrium position.

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Answer:

Fe_2O_3+3CO\Rightarrow \:2Fe+3CO_2

Explanation:

Fe_2O_3+CO\Rightarrow \:2Fe+CO_2\\\\Fe_2O_3+3CO\Rightarrow \:2Fe+3CO_2

Best Regards!

8 0
3 years ago
3. Identify the spectator ion(s) in the following reaction.
Arlecino [84]
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3 0
3 years ago
An aqueous potassium iodate ( KIO3 ) solution is made by dissolving 562 562 grams of KIO 3 KIO3 in sufficient water so that the
maxonik [38]

Answer:

Molarity of KIO_{3} solution is 0.612 mol/L

Explanation:

Number of moles of a substance = (mass of substance)/(molar mass of the substance)

Molar mass of KIO_{3} = 214 g/mol

So, 562 g of KIO_{3} = \frac{562}{214} moles of KIO_{3} = 2.63 moles of KIO_{3}

Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)

Here solute is KIO_{3} and solvent is water

Total volume of solution is 4.30 L

So, molarity of KIO_{3} solution = \frac{2.63}{4.30}mol/L = 0.612 mol/L

3 0
3 years ago
List the number of each type of atom on the left side of the equation 2C6H14(l)+19O2(g)→12CO2(g)+14H2O(g) Enter your answers sep
murzikaleks [220]

<u>Answer:</u> The number of carbon, hydrogen and oxygen atoms on the left side of the reaction are 12, 28 and 38 respectively

<u>Explanation:</u>

In a chemical equation, the chemical species are termed as reactants or products.

Reactants are defined as the species which react in the reaction and are written on the left side of the reaction arrow.

Products are defined as the species which are produced in the reaction and are written on the right side of the reaction arrow.

For the given chemical equation:

2C_6H_{14}(l)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(g)

On the reactant side:

Number of carbon atoms = (6 × 2) = 12

Number of hydrogen atoms = (14 × 2) = 28

Number of oxygen atoms = (2 × 19) = 38

Hence, the number of carbon, hydrogen and oxygen atoms on the left side of the reaction are 12, 28 and 38 respectively

3 0
4 years ago
What is The atomic mass number of tin
san4es73 [151]

Answer:

50

Explanation:

The atomic number is 50

3 0
3 years ago
Read 2 more answers
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