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vodomira [7]
2 years ago
5

Jacob subjects 11 liters of gas that he collected at 1.78 atm to an environment that

Chemistry
1 answer:
eduard2 years ago
4 0

Considering the Boyle's law,the volume of the new sample of gas will be 19.778 atm.

<h3>Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant. This law says that the pressure of a gas in a closed container is inversely proportional to the volume of the container: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Having an initial state 1 and a final state 2, the following is true:

P1×V1=P2×V2

<h3>New volume</h3>

In this case, you know:

  • P1= 1.78 atm
  • V1= 11 L
  • P2= 0.99 atm
  • V2= ?

Replacing in Boyle's law:

1.78 atm× 11 L=0.99 atm× V2

Solving:

(1.78 atm× 11 L)÷ 0.99 atm=V2

<u><em>19.778 atm= V2</em></u>

Finally, the volume of the new sample of gas will be 19.778 atm.

Learn more about Boyle's law:

brainly.com/question/4147359

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A molecular orbital that decreases the electron density between two nuclei is said to be <u>antibonding.</u>

The bonding orbital, which would be more stable and encourages the bonding of the two H atoms into H_{2}, is the orbital that is located in a less energetic state than just the electron shells of the separate atoms. The antibonding orbital, which has higher energy but is less stable, resists bonding when it is occupied.

An asterisk (sigma*) is placed next to the corresponding kind of molecular orbital to indicate an antibonding orbital. The antibonding orbital known as * would be connected to sigma orbitals, as well as antibonding pi orbitals are known as \pi* orbitals.

Therefore,  molecular orbital that decreases the electron density between two nuclei is said to be <u>antibonding.</u>

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Hence, the correct answer will be option (b)

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