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PSYCHO15rus [73]
3 years ago
13

What is the name of the following compound - AgNO3 *

Chemistry
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

Silver Nitrate

Explanation:

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The density of water is 1.0 grams per milliliter. What can you conclude from this simulation about whether an object will
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The density of water is 1.0 grams per milliliter then it will be sink in water

Density is a word we use to describe how much space an object or substance takes up in the volume and in relation to the amount of matter in that object or substance its mass) and another way to put it is that density is the amount of mass per unit of volume

Here given density is 1.0 grams per milliliter and it will be sink in water because the density of water in 1.0 g/ml and this object is more dense than water and the density of an object determines whether it will float or sink in another substance and an object will float if it is less dense than the liquid it is placed in and an object will sink if it is more dense than the liquid it is placed

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A vector is represented as a ____​
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I hope this helped you have a good day

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A substance is less dense than water, it will_____ to the________
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3 years ago
For the reaction N2 + 3H2 = 2NH3, if you have 2.00 moles of N2 and 4.00 moles of H2 : a. Identify the limiting reactant. _______
EastWind [94]

Answer:

The answer to your question is below

Explanation:

For the reaction N2 + 3H2 = 2NH3, if you have 2.00 moles of N2 and 4.00 moles of H2 : a. Identify the limiting reactant. ____________

                                   N2     +     3H2      =      2NH3

                                 1 mol         3 moles        2 moles

Given                       2 moles     4 moles

   

       Rule of three for N2

                    x =  (2 x 3) / 1 = 6 mol  of H2, it means that is needed 6 moles of H2 and there are only 4, so the limiting reactant is H2                                

b. How many moles of NH3 can be formed? ____________

           rule of three

                                3 moles of H2 ---------------------  2 moles of NH3              

                                4 moles of H2  ---------------------   x

                     x = (4x2)/3 = 2.7 moles of NH3 are formed

c. How many moles of the excess reactant will remain? _________

      x = (4 x 1) / 3     =  1.33

Excess reactant = 2 - 1.33 = 0.67 moles                  

   

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