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borishaifa [10]
3 years ago
15

what does NaBr + Ca(OH)2 -> CaBr2 + NaOH make, what rection for an example rust. is it aa chemical reaction? please reply asa

p ty sm
Chemistry
2 answers:
yuradex [85]3 years ago
4 0
Formula for rust is FE203.XH20.
Semenov [28]3 years ago
3 0

FORMULA FOR RUST IS FE2O3.XH20

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Please help me thank you :)
LenaWriter [7]

Answer:

D. 3220

Explanation:

1 km equals 1000 m, so 3.22 km is

3220 m

5 0
3 years ago
Read 2 more answers
What is one observation you can make aboit venus​
PilotLPTM [1.2K]

Answer:

The temperature is very hot.

Explanation:

The gas around the planet traps the suns heat and makes it the hottest planet in our solar system.

8 0
3 years ago
Please show the work :(What is the estimated force applied to the box if the acceleration is .40 m/s2?
lara31 [8.8K]

Answer:

20N

Explanation:

Given parameters:

        Force(N)     Acceleration(m/s²)  

            10                   0.2

           ?                      0.4

Unknown:

The force applied when the acceleration is 0.4m/s²

Solution:

From newton's second law of motion;

 Force = mass x acceleration

 Since we are using the same box, let us find the mass of the box;

      Force  = mass x acceleration

         10 = mass x 0.2

            mass = \frac{10}{0.2}  = 50kg

Now,

 The force in the second instance will be;

      Force  = 50 x 0.4  = 20N

8 0
2 years ago
Which of the following is a property of a pure substance?
wolverine [178]
D.) the original components retain their individual properties
8 0
3 years ago
Read 2 more answers
PLEASE HELP
swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

5 0
3 years ago
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