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kolbaska11 [484]
3 years ago
13

7823 multiply10 to the power of 3.​

Mathematics
1 answer:
marshall27 [118]3 years ago
5 0
The answer is 7,823,000
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The length of a rectangular computer chip is 22 x 10 cm and the width is 7 x 104 cm. Explain how to
mash [69]

Answer:

area = 160160 inches²

area = 1.6016 × 10⁵ inches²

Step-by-step explanation:

The length of the rectangular computer chip is 22 × 10 cm and the width is 7 × 104 cm .  

The area of the rectangular computer chip is the product of the length and the width.

area = length × width

area = (22 × 10) × (7 × 104)  

area = 220 × 728

area = 160160  inches²

In scientific notation

area = 1.6016 × 10⁵ inches²

160160 is written as 1.6016 × 10⁵ because 1.60160 × 100000 = 1.6016 × 10⁵

7 0
3 years ago
∠1 and ∠2 are vertical angles. If m∠2 = 124°, find the measure of the supplement of ∠1 plzzz i need help
Veronika [31]

Answer:

∠1 = 124 degrees

Step-by-step explanation:

Vertical angles are always congruent

So ∠1  = ∠2

6 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form for the line that passes through (1, 1), and is perpendicular to the graph of 3x + 2y
defon

Answer:

2X-3Y = -1

Step-by-step explanation:

given equation is 3X +2Y = -7

FIRST BRING THIS IN SLOPE INTERCEPT FORM

2Y = -3X -7

DIVIDING EACH TERM BY 2

Y = (-3/2)X -7/2

SLOPE OF GIVEN EQUATION IS -3/2

SLOPE OF LINE PERPENDICULAR TO THIS IS NEGATIVE RECIPROCAL HENCE  SLOPE OF REQUIRED EQUATION IS 2/3

EQUATION OF STRAIGHT LINE IN POINT SLOPE FORM IS

Y-Y1 = m(X-X1)

Y-1 = (2/3)(X-1)

MULTIPLYING ALL TERMS BY 3

3(Y-1) = 2(X-1)

3Y-3 = 2X -2

2X-2 = 3Y-3

2X-3Y =-3+2

2X-3Y = -1

8 0
3 years ago
Read 2 more answers
city high school had a student reduction and lost 3/4 of its students. if 87 of its students were left after the reduction, how
Westkost [7]
There were 116 students originally
7 0
3 years ago
Which two values of x are roots of the polynomial below?<br> 3x2-3x+1
QveST [7]

Answer:

The roots are

x=\frac{1}{6} [3+ i\sqrt{3}]

x=\frac{1}{6} [3- i\sqrt{3}]

Step-by-step explanation:

we have

3x^2-3x+1

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2-3x+1=0  

so

a=3\\b=-3\\c=1

substitute in the formula

x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}

x=\frac{3\pm\sqrt{-3}} {6}

Remember that

i=\sqrt{-1}

so

x=\frac{1}{6} [3\pm i\sqrt{3}]

The roots are

x=\frac{1}{6} [3+ i\sqrt{3}]

x=\frac{1}{6} [3- i\sqrt{3}]

6 0
3 years ago
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