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kolbaska11 [484]
3 years ago
13

7823 multiply10 to the power of 3.​

Mathematics
1 answer:
marshall27 [118]3 years ago
5 0
The answer is 7,823,000
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Help me please ill give brainliest give the CORRECT answer please
Neporo4naja [7]

Answer:

  174 ft²

Step-by-step explanation:

Assuming you're interested in the area of the figure, you can compute it as the sum of the areas of the triangle and rectangle.

The unknown side of the triangle can be figured from the overall dimension of the rectangle and the two lengths that are not part of the triangle base:

  6 ft + triangle base + 6 ft = 18 ft

  triangle base = 18 ft - 12 ft = 6 ft

Then the area of the triangle is ...

  A = 1/2bh = 1/2(6 ft)(4 ft) = 12 ft²

__

Of course, the area of the rectangle is the product of its length and width:

  A = LW = (18 ft)(9 ft) = 162 ft²

__

The total area of the figure is the sum of these:

  area = triangle area + rectangle area

  area = 12 ft² +162 ft²

  area = 174 ft²

3 0
3 years ago
Helpppppp pl for 5 point​
Tcecarenko [31]

Answer:

3^{-2} * 3^3

Step-by-step explanation:

Multiply 1/9 and 27 to get 27/9 which reduces to 3. When doing these equations, you add up the exponents. To get 3, you would have to have 3^1. The get this, the only equation that would work is 3^-2 x 3^3

-2+3 gets 1. So 3^1 which gets you 3. So this is the answer.

4 0
2 years ago
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran
Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0
3 years ago
Plssss helppp meeeeee
defon
The last one
Jfjjdjdjjdjfjjdjdjjdjxj
7 0
3 years ago
Pls help Im very stuck on this and don’t understand
Lady bird [3.3K]

Answer:

C. 85 degrees

Step-by-step explanation:

Step 1: Set up equation

x + 57 + 96 + x = 131

Step 2: Solve for <em>x</em>

2x + 153 = 131

2x = -22

x = -11

Step 3: Find m∠RQU

m∠RQU = 96 + <em>x</em>

m∠RQU = 96 - 11

m∠RQU = 85°

8 0
3 years ago
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