All categories

2 years ago

Round the decimal equivalent of 856 1/6 to the nearest hundredth. What number is in the hundredth place PLEASE HELP

Mathematics

1 answer:

Vika [28.1K]2 years ago

7 0

Answer:

The answer is 856.17.

Step-by-step explanation:

If you made the fraction into a decimal, you would get 856.166666666. If you round it to the nearest hundredth, you would get 856.17.

You might be interested in

What is the surface area of the square pyramid? A. 2480 in2 B. 5120 in2 C. 6880 in2 D. 8640 in2

DedPeter [7]

Hello is there anything more like the high or the base because i can't solve it like that without anything

6 0

3 years ago

(05.01)Which equation can be used to calculate the area of the shaded triangle in the figure below?

Marina86 [1]

Equation of shaded triangle is $\frac{1}{2} (14\times8)$ .

Solution:

Length of the rectangle = 14 ft

Breadth of the rectangle = 8 ft

Area of the rectangle = length × breadth

= 14 × 8

In this rectangle the diagonal splits the rectangle into two equal halves.

Area of the shaded triangle = Half of area of rectangle

$$=\frac{1}{2} (14\times8)$

Area of the shaded triangle = $\frac{1}{2} (14\times8)$

Hence the equation can be used to calculate the area of the shaded

triangle is $\frac{1}{2} (14\times8)$ .

7 0

3 years ago

37 is 50% of what number?

elena-s [515]

You can calculate that as (x * 50)/100 = 37

x*50 = 3700

x=74

8 0

3 years ago

Read 2 more answers

How many batches of ravioli can I make , from 1 gallon at $1.80 that requires 24 ounces

Olin [163]

Answer:

Step-by-step explanation:

You can make 5 batches because theres 128 ounces in one gallon so youd divide 128 by 4 and get 5.333 etc. Then youd round to the nearest whole number.

6 0

2 years ago

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$

4 0

3 years ago