The product of 8 and a number q is at least 32

What is the image of −6,3)<br> (−6,3) after a reflection over the y-axis?

Umnica [9.8K]

The image is (6,3) after a reflection over the y-axis

5 0

3 years ago

The wheels on Darlene's car have on 11-inch radius. If the wheels are rotating at a rate of 378 rpm, find the linear speed in mi

elena-s [515]

Answer:

The linear speed in which Darlene is traveling is 24.74 miles per hour.

Step-by-step explanation:

The wheel experiments rolling, which is a combination of translation and rotation. The point where linear speed happens is located at geometrical center of the wheel and instantaneous center of rotation is located at the point of contact between wheel and ground. The linear speed ( $v$ ), measured in inches per second, is defined by following expression:

$v = R\cdot \omega$ (1)

Where:

$R$ - Radius of the wheel, measured in inches.

$\omega$ - Angular speed, measured in radians per second.

If we know that $R = 11\,in$ and $\omega \approx 39.584\,\frac{rad}{s}$ , then the linear speed, measured in miles per hour, in which Darlene is traveling is:

$v = 11\,in\times \frac{1\,mi}{63360\,in} \times 39.584\,\frac{rad}{s}\times \frac{3600\,s}{h}$

$v \approx 24.74\,\frac{mi}{h}$

The linear speed in which Darlene is traveling is 24.74 miles per hour.

8 0

3 years ago

Y - (-9) = 8?<br><br> I am confused

Yuki888 [10]

Answer:

y = -1

Step-by-step explanation:

y - ( - 9) = 8

y + 9 = 8

y = 8 - 9

y = -1

- ( - turns to + because you are subtracting a negative number

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-Chetan K

4 0

3 years ago

Read 2 more answers

Use Cramer's Rule to solve the following system: –2x – 6y = –26 5x + 2y = 13

andriy [413]

$\bf \begin{cases}
-2x-6y&=-26\\
\quad 5x+2y&=13
\end{cases}\stackrel{\textit{determinant of the coefficients}}{D=
\begin{bmatrix}
-2&-6\\5&2
\end{bmatrix}}\implies (-4)-(-30)
\\\\\\
D=-4+30\implies \boxed{D=26}\\\\
-------------------------------\\\\$

$\bf x=\cfrac{D_x}{D}\implies x=\cfrac{
\begin{bmatrix}
\boxed{-26}&-6\\\\ \boxed{13}&2
\end{bmatrix}}{D}\implies x=\cfrac{(-52)-(-78)}{26}
\\\\\\
x=\cfrac{-52+78}{26}\implies x=\cfrac{26}{26}\implies \boxed{x=1}\\\\
-------------------------------\\\\
y=\cfrac{D_y}{D}\implies y=\cfrac{
\begin{bmatrix}
-2&\boxed{-26}\\\\ 5&\boxed{13}
\end{bmatrix}}{D}\implies y=\cfrac{(-26)-(-130)}{26}
\\\\\\
y=\cfrac{-26+130}{26}\implies y=\cfrac{104}{26}\implies \boxed{y=4}$

4 0

3 years ago

Zoe used 3/8 of her ribbon to wrap a present. If she uses 9 feet of ribbon for the present how much ribbon did Zoe have it first

MArishka [77]

Let the total ribbon Zoe had was x feet.

Out of x feet, she used 3/8 part of it.

Hence, $\frac{3x}{8}$