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Alexxx [7]
4 years ago
13

How many times does 6 go in to 24

Mathematics
2 answers:
Sindrei [870]4 years ago
8 0
The answer is 4
6+6+6+6=24
Lena [83]4 years ago
7 0

Answer:

4 times

Step-by-step explanation:

24 = 6+6+6+6

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What is square root in simplified form? What is in simplified form?
Anon25 [30]

Answer:

Step-by-step explanation:

Let as us 45 as the number we should use to get the square root in the simplest form

And then 144

The square root of a number in is simplest form means to get the number inside the radical as low as possible

8 0
4 years ago
The sine of 67 degrees is 0.92. what is the cosine of 23 degrees?
patriot [66]

Answer:

Cos23° is -0.532833...........

7 0
3 years ago
Read 2 more answers
An example of consecutive odd integers is 23, 25, 27, and 29. Find four consecutive odd integers with a sum of 160. Show your wo
Andrew [12]
Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.

Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.

Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7 

Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18

Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.

Answer: 37,39,41,43

8 0
3 years ago
-5s=−13<br> solve for s .
Marizza181 [45]

Answer:

The answer is going to be 13/5 or 2.6

Step-by-step explanation:

You are going to need to divide both sides by the constant of -5 in order to get s by itsef. After you divide both sides by -5, you will get -13/-5 which two negatives divided by a positive so it would be 13/5 or if you turn it into an integer, it would be 2.6

7 0
3 years ago
A professor wants to know whether or not there is a difference in comprehension of a lab assignment among students depending on
san4es73 [151]

Answer:

It is concluded that no difference exists in the comprehension of the lab based on the test scores.

Step-by-step explanation:

<em><u>Let the populations be normally distributed with a populations standard deviation of 5.32 points for both the text and visual illustrations.</u></em>

The above statement tells us that the independent t or two sample t test will be performed as both have equal variances and are normally distributed.

This can be easily done through excel.

The following table is obtained

     

t-Test: Two-Sample Assuming Equal Variances  

 

                <u>  Text                      Visual Illustrations</u>

Mean          70.28                       75.08

Variance 304.48                     228.58

Observations 15                             15

Pooled Variance Sp²= 266.53

       Pooled Standard Deviation = Sp = 16.33

Hypothesized Mean Difference = x1`-x2`= 0

df = n1+n2-2= 15+15-2= 30-2= 28

t Stat -0.805188239

<u>P(T<=t) two-tail 0.427495979                      </u>

<u>t Critical two-tail 1.701130908                              </u>

Let the null and alternate hypotheses be

H0 : u1-u2= 0   against the claim Ha: u1-u2≠0

There is no difference between the means

against the claim

that there is a difference in means of a lab assignment among students depending on if the instructions are given all in text, or if they are given primarily with visual illustrations.

The significance level is ∝= 0.1

The d.f is n1+n2-2= 15+15-2= 30-2=28

This is a two tailed test and the critical region is t (0.025) (28) ≥ 1.7011 and  t (0.025) (28) ≤ - 1.7011.

The test statistic is

t= x1-x2/ Sp √1/n1+ 1/n2

t= 70.28 -75.08/ 16.33√1/15 +1/15

t= -4.8/5.963

t= -0.8049811  ( minute difference from excel result due to rounding)

Since the calculated value of t= -0.8049 does not fall in the critical region we conclude that there is no difference in means of a lab assignment among students depending on if the instructions are given all in text, or if they are given primarily with visual illustrations.

We accept the null hypothesis.

The p- value is 0.427495979.

8 0
3 years ago
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