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ludmilkaskok [199]
3 years ago
8

25. Why does increasing concentration usually increase reaction rate?

Chemistry
1 answer:
wlad13 [49]3 years ago
8 0

There are more particle collisions when increasing concentration. This causes an increase in reaction.

Hope this helps you!

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In an era of bad harvests, famine, and rioting, the French government took steps to improve the worsening financial crisis. What
sukhopar [10]

Answer:

The government raised taxes

Explanation:

France had monarchy as its form of government. After the King of France had borrowed heavily to retain his extravagant lifestyle as well as the fact that the Kingdom of France was largely indebted, the king had no other option but to increase taxes paid by commoners in France.

This happened in an era of bad harvests and famine. The commoners depended mostly on bread to survive. This made the cost of bread to alarmingly increase and most people were hungry and starving.

These happenings led to the French revolution.

4 0
3 years ago
Read 2 more answers
A negative ion is (larger/smaller) than its parent atom.<br> Why?
Kay [80]

Answer:

When an atom attracts extra electrons it becomes a negative ion. The negative ion is larger than the original atom. The positive nucleus remains the same, with the same attractive force. However, this attractive force is now pulling on more electrons and therefore has less effect.

Or

Positive ions are formed by removing one or more electrons from the outermost region of the atom. The opposite is true of negative ions. When electrons are added to form an anion, the increased electron-electron repulsions cause the electrons to spread out more in space. Thus, anions are larger than their parent atoms.

5 0
3 years ago
Is O2 covalent molecular or polar covalent
Dimas [21]
Yes it yes molusbus ks jshs jsbjsus js js sjs js sj dis dis jsys snsus
6 0
3 years ago
Help! 7th Grade Math!
vagabundo [1.1K]

Answer:

D

Explanation: Trust me

6 0
3 years ago
WILL MARK BRAINLIEST!!!!
Lyrx [107]

Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Compounds
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})
  2. [DA] Divide [Cancel out units]:                                                                         \displaystyle 5.7015 \ mol \ K_2SO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

7 0
3 years ago
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