6. The fusion of 4 H-1 nuclei to produce two positrons and one other nuclei.
1 answer:
You might be interested in
Answer: The equilibrium constant for the given reaction is 0.0421.
Explanation:
Concentration of = 0.0095 M
Concentration of = 0.020 M
Concentration of = 0.020 M
The expression of the equilibrium constant is given as:
(An equilibrium constant is an unit less constant)
The equilibrium constant for the given reaction is 0.0421.
Given that, an experiment to measure the enthalpy change for the reaction of aqueous copper(II) sulfate, CuSO4(aq) and zinc, Zn(s) was carried out in a coffee cup calorimeter; the heat of the reaction in the whole system is calculated to be 2218.34 kJ
Heat of reaction (i.e enthalpy of reaction) is the quantity of heat that is required to be added or removed when a chemical reaction is taken place in order to maintain all of the compounds present at the same temperature.
The formula used to calculate the heat of the reaction can be expressed as follows:
Q = mcΔT
where:
- Q = quantity of heat transfer
- m = mass
- c = specific heat of water = 4.18 kJ/g °C (constant)
- ΔT = change in temparature
From the information given:
- The initial temperature (T₁) = 25° C
- The final temperature (T₂) = 91.5° C
∴
The change in temperature i.e. ΔT = T₂ - T₁
ΔT = 91.5° C - 25° C
ΔT = 66.5° C
The number of moles of CuSO₄ = 1.00 mol/dm³ × 50.0 cm³
= 0.05 moles
- Since the molar mass of CuSO₄ = 159.609 g/mol
Then;
Using the relation:
By crossing multiplying;
mass of CuSO₄ = number of moles of CuSO₄ × molar mass of CuSO₄
mass of CuSO₄ = 0.05 moles × 159.609 g/moles
mass of CuSO₄ = 7.9805 grams
∴
Using the formula from above:
Q = mcΔT
Q = 7.9805 g × 4.18 kJ/g °C × 66.5° C
Q = 2218.34 kJ
Therefore, we can conclude that the heat of the reaction is 2218.34 kJ
Learn more about the chemical reaction here:
This is an incomplete question, here is a complete question.
Nitroglycerine (C₃H₅N₃O₉) explodes with tremendous force due to the numerous gaseous products. The equation for the explosion of Nitroglycerine is:
A scientist conducts an experiment to characterize a bomb containing nitroglycerine. She uses a steel, ridge container for the test.
Volume of rigid steel container: 1.00 L
Molar mass of Nitroglycerine: 227 g/mol
Temperature: 300 K
Amount of Nitroglycerine tested: 227 g
Value for ideal gas constant, R: 0.0821 L.atm/mol.K
In a second experiment, the total pressure is observed to be 58 atm. what is the partial pressure of the water vapor produced?
Answer : The partial pressure of the water vapor is, 20.01 atm
Explanation :
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical reaction is:
From the balanced chemical reaction we conclude that,
As, 4 moles of react to give 12 moles of
So, 1 moles of react to give
moles of
and,
As, 4 moles of react to give 1 moles of
So, 1 moles of react to give
moles of
and,
As, 4 moles of react to give 6 moles of
So, 1 moles of react to give
moles of
and,
As, 4 moles of react to give 10 moles of
So, 1 moles of react to give
moles of
Now we have to calculate the mole fraction of water.
Now we have to calculate the partial pressure of the water vapor.
According to the Raoult's law,
where,
= partial pressure of water vapor gas = ?
= total pressure of gas = 58 atm
= mole fraction of water vapor gas = 0.345
Now put all the given values in the above formula, we get:
Therefore, the partial pressure of the water vapor is, 20.01 atm