Explanation:
An IC engines means an Internal Combustion engine. Here, the combustion takes place in side a chamber or a cylinder internally, hence it is known as internal combustion engine.
Combustion is the process where oxygen reacts with the fuel and it burns to produce a large amount of force and heat. In each revolution of the crank, the engine creates a power stroke when the piston goes from the bottom dead center to the top dead center.
During each power stroke, the energy released forces the piston down and the crankshaft is rotated.
0N. The net force acting on this firework is 0.
The key to solve this problem is using the net force formula based on the diagram shown in the image. Fnet = F1 + F2.....Fn.
Based on the free-body diagram, we have:
The force of gases is Fgases = 9,452N
The force of the rocket Frocket = -9452
Then, the net force acting is:
Fnet = Fgases + Frocket
Fnet = 9,452N - 9,452N = 0N
Wow! Very simple. Use the equation for momentum which is p=mv. You know your momentum and velocity, so do 120=m(4), now solve for m, which is 30. The mass of the child is 30 kg
Answer:
option d is correct
work done is 647 J
Explanation:
Given data
pressure P = 3 atm
volume V1 = 2 L
volume V2 = 8 L
to find out
work is done by the gas
solution
we know that work done formula that is
work done = k ( 
- 
) / n
here n = 1 - γ
and k = PV^γ
and we know for diatomic gas γ = 1.4
so k will be = ( 3× 101325 ) × 
k = 50.62
so that now
work done = k ( - ) / n
work done = 50.62 ( 
- 
) / 1-1.4
so work done will be 647 J
so option d is correct
work done is 647 J
