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love history [14]
10 months ago
10

write the balanced molecular chemical equation for the reaction in aqueous solution for sodium hydroxide and tin(iv) acetate. if

no reaction occurs, simply write only nr. be sure to include the proper phases for all species within the reaction.
Chemistry
1 answer:
dimaraw [331]10 months ago
5 0

The reaction of Sodium hydroxide and Tin(iv) acetate is as follows:

Sodium Hydroxide + Tin(IV) Acetate = Sodium Acetate + Tin(IV) Hydroxide

NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4

<u>Balanced Chemical Equation</u>:

4NaOH + Sn(C2H3O2)4 → 4C2H3NaO2 + Sn(OH)4

What is an Aqueous solution?

An aqueous solution is one in which water serves as the solvent. It is also known as a water-based solution. Many common chemical substances are dissolved in water, and these are called aqueous solutions. Examples of aqueous solutions include saltwater, vinegar, and sugar water.

What is Sodium hydroxide?

Sodium hydroxide, also known as lye or caustic soda, is a white, solid crystalline substance used in a number of industrial and household applications. It is a strong base that is highly soluble in water and can be used to adjust the pH of a solution. It is also used in the manufacture of soaps, detergents, and cleaning products.

What is Tin(IV)?

Tin(IV) is the chemical name for tin, which is a chemical element with the atomic number of 50. It is a silvery-white, malleable metal that is used in a variety of applications, including alloys, solders, and some electronics.

To know more about Sodium hydroxide,

LINK- brainly.com/question/29509565

CODE- #SPJ4

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Would a screwdriver be an example of technology? Why or why not?
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Read 2 more answers
Air-bags can be inflated by the decomposition of sodium azide, NaN3. At 25.0◦C and 1.10 atm, what volume of N2(g) is produced by
Mashcka [7]

Answer:

V = 36.7L of N_{2}

Explanation:

1. Write the chemical reaction for the decomposition of sodium azide:

_{2}NaN_{3}(l)=_{2}Na(s)+_{3}N_{2}(g)

2. Find the number of moles of N_{2} produced by the decomposition of 71.4g of NaN_{3}:

71.4gNaN_{3}*\frac{1molNaN_{3}}{65gNaN_{3}}*\frac{3molesN_{2}}{2molesNaN_{3}}=1.65molesN_{2}

3. Use the ideal gas equation to find the Volume of N_{2} occupied by 1.65 moles of N_{2}, at the temperature and pressure given by the problem:

PV=nRT

Solving for V:

V=\frac{nRT}{P}

Converting the temperature from ◦C to K:

25◦C+273.15=298.15K

Replacing values:

V=\frac{1.65mol*(0.082\frac{atm.L}{mol.K})*298.15K}{1.10atm}

V=36.7L of N_{2}

4 0
3 years ago
Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of potassium hydroxide and nickel
Gnom [1K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of nickel (II) acetate and potassium hydroxide is given as:

Ni(CH_3COO)_2(aq.)+2KOH(aq.)\rightarrow 2CH_3COOK(aq.)+Ni(NO_3)_2(s)

Ionic form of the above equation follows:

Ni^{2+}(aq.)+2CH_3COO^-(aq.)+2K^+(aq.)+2OH^-(aq.)\rightarrow 2CH_3COO^-(aq.)+2K^+(aq.)+Ni(OH)_2(s)

As, acetate and potassium ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Ni^{2+}(aq.)+2OH^-(aq.)\rightarrow Ni(OH)_2(s)

Hence, the net ionic equation is written above.

4 0
2 years ago
Pressure of gas in kilopascals
Pavlova-9 [17]
Use the formula (P1V1)/T1 = (P2V2)/T2
(12.8 * 100)/(-108 + 273) = (.855 * P2)/(22 + 273)  Need to convert Celsius into Kelvins
1280/165 = (0.855 * P2)/295
7.755556 = 0.002898 * P2
P2 = 2676.18 kPa
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7 0
2 years ago
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