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love history [14]
1 year ago
10

write the balanced molecular chemical equation for the reaction in aqueous solution for sodium hydroxide and tin(iv) acetate. if

no reaction occurs, simply write only nr. be sure to include the proper phases for all species within the reaction.
Chemistry
1 answer:
dimaraw [331]1 year ago
5 0

The reaction of Sodium hydroxide and Tin(iv) acetate is as follows:

Sodium Hydroxide + Tin(IV) Acetate = Sodium Acetate + Tin(IV) Hydroxide

NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4

<u>Balanced Chemical Equation</u>:

4NaOH + Sn(C2H3O2)4 → 4C2H3NaO2 + Sn(OH)4

What is an Aqueous solution?

An aqueous solution is one in which water serves as the solvent. It is also known as a water-based solution. Many common chemical substances are dissolved in water, and these are called aqueous solutions. Examples of aqueous solutions include saltwater, vinegar, and sugar water.

What is Sodium hydroxide?

Sodium hydroxide, also known as lye or caustic soda, is a white, solid crystalline substance used in a number of industrial and household applications. It is a strong base that is highly soluble in water and can be used to adjust the pH of a solution. It is also used in the manufacture of soaps, detergents, and cleaning products.

What is Tin(IV)?

Tin(IV) is the chemical name for tin, which is a chemical element with the atomic number of 50. It is a silvery-white, malleable metal that is used in a variety of applications, including alloys, solders, and some electronics.

To know more about Sodium hydroxide,

LINK- brainly.com/question/29509565

CODE- #SPJ4

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6.00 moles of sodium perchlorate contains the same number of atoms as __________. 6.00 moles of sodium perchlorate contains the
Ksju [112]

Answer:

6.00 moles of sodium permanganate

Explanation:

Let us attempt to count the number of atoms present in sodium perchlorate. The formula of the compound is NaClO4

Sodium atoms - 1

Chlorine atoms - 1

Oxygen atoms -4

Total number of atoms = 6

Among the options, only KMnO4 also has six atoms. One atom of potassium, one atom of manganese and four atoms of oxygen.

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3 years ago
He reaction produces 1.6 g of gas in 30 seconds.Calculate the mean rate of the reaction in the first 30 seconds.Use the equation
devlian [24]

Answer:

Mean rate of reaction produced = 0.533 g/sec (approx.)

Explanation:

Given:

Reaction produced = 1.6 gram

Time taken = 30 sec

Find:

Mean rate of reaction produced

Computation:

Mean rate of reaction produced = Reaction produced / Time taken

Mean rate of reaction produced = 1.6 / 30

Mean rate of reaction produced = 0.533 g/sec (approx.)

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30. The density of an unknown gas at 27°C and 2 atm pressure is equal with density of N2 gas at
Zanzabum

Answer:

Molar mass of the unknown gas is 64.6 g/mol

Explanation:

Let's think this excersise with the Ideal Gases Law.

We start from the N₂. At STP conditions we know that 1 mol of anything occupies 22.4L.

We apply: P . V = n . R . T

5 atm . V = 1 mol . 0.082 . 325K

V = (1 mol . 0.082 . 325K) / 5 atm = 5.33 L

It is reasonable to say that, if we have more pressure, we may have less volume.

As this is the volume for 1 mol of N₂, our mass is 28 g. Then, the density of the nitrogen and the unknown gas is 28 g/5.33L = 5.25 g/L

Our unknown gas has, this density at 27°C and 2 atm.

If we star from this, again: 1 mol of any gas occupy 22.4L at STP, we can calculate the volume for 1 mol at those conditions:

P₁ . V₁ / T₁ = P₂ . V₂ / T₂

1 atm . 22,4L / 273K = 2 atm . V₂ / 300K

Remember that the value for T° is Absolute (T°C + 273)

[ (1 atm . 22.4L / 273K) . 300K] / 2 atm = V₂ → 12.3L

This is the volume for 1 mol of the unknown gas at 2 atm and 27°C

We use density to determine the mass: 12.3 L . 5.25 g/L = 64.6 g

That's the molar mass: 64.6 g/mol

6 0
2 years ago
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