Yuck, trig. I'm doing college trig at this very moment.
the top half (1+(2sinθ)cosθ)=1+sin(2θ)
because 2sinθcosθ=sin(2θ) is an identity
Using polynomial division your answer becomes:
(csc θ)(sec θ)+2
Answer:
dy/dx = -b/a cot α
Step-by-step explanation:
x² / a² + y² / b² = 1
Take derivative with respect to x.
2x / a² + 2y / b² dy/dx = 0
2y / b² dy/dx = -2x / a²
dy/dx = -b²x / (a²y)
Substitute:
dy/dx = -b²a cos α / (a²b sin α)
dy/dx = -b cos α / (a sin α)
dy/dx = -b/a cot α
2nd answer.
any pts in the shaded region satisfies your simultaneous equation.
Answer:
see explanation
Step-by-step explanation:
The area (A) of the square = s² ( s is the measure of the side )
Here s = x + 2 and A = 7 , thus
(x + 2)² = 7 ← expand left side using FOIL
x² + 4x + 4 = 7 ( subtract 4 from both sides )
x² + 4x = 3 ← as required
Answer: y= 5/2(x-2)^2 - 1
Step-by-step explanation:
y=a(x-2)^2 - 5
5=a(0-2)^2 - 5
10=a(-2)^2
10=a4
a=10/4 or 5/2
