1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andru [333]
3 years ago
9

Convert 11.03 moles of calcium nitrate to grams

Chemistry
2 answers:
hichkok12 [17]3 years ago
6 0
Im pretty sure the answer is <span> 0.01218859659g

not 100% sure tho so please consult someone else b4 answering 
i hope this helps!!</span>
KiRa [710]3 years ago
6 0
1809.8884339999997 grams
You might be interested in
The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.
kumpel [21]

Answer:

a) 52.8

Explanation:

M1V1 = M2V2

(7.91 M)(x ml) = (2.13 M) (196.1 ml)

(7.91M) (xml) = 417.693 M.ml

x ml = 417.693/ 7.91

x   =  52.8

6 0
3 years ago
Read 2 more answers
If you increase the temperature of a reaction, then the reaction rate will ...
DIA [1.3K]
The answer is B.Increase
6 0
3 years ago
Do you think one mole of the different substances has the same amount?​
vagabundo [1.1K]

It's because of Avagadro's number.

  • It is known as Avagadro's constant too.
  • It states that at constant temperature one mole of any substance contain same number of atoms i.e n no of atoms

where

\\ \sf\longmapsto n=6.022\times 10^{23}

5 0
2 years ago
What is the molar mass of a gas if a flask with a volume of 3. 16 l contains 9. 33 grams of the gas at 32. 0°c and 1. 00 atm?
Serhud [2]

The molar mass of a gas if a flask with a volume of 3. 16 L contains 9. 33 grams of the gas at 32. 0°C and 1. 00 atm is  1.17g/mol

Calculation ,

In this question we have to fist find the number of moles of gas by using ideal gas equation and from the help of number of moles we can determine molar mass.

According to ideal gas equation which is also known as ideal law ,

PV = nRT                ...( i )

where P is the pressure of the gas = 1 atm

V is the volume of the gas in the flask with volume =  3. 16 L

R is the universal gas constant = 0.082 atm L/K mol

T is the temperature = 32. 0°C = 32 + 273 = 305 K

n is the number of moles = ?

Putting the value of Pressure P , volume V , temperature T , number of moles n and universal gas constant R in the equation (i) we get ,

1 atm ×3. 16 L = n× 0.082 atm L/K mol ×305 K

n = 1 atm ×3. 16 L / 0.082 atm L/K mol × 305 K = 0.126 mole

number of mole of a gas  = 0.126 mole = given mass/ molar mass

molar mass  = number of moles × Given mass =  0.126 × 9. 33 = 1.17g/mol

Learn about flask

brainly.com/question/14161066

#SPJ4

7 0
1 year ago
What would be the effect on your calculated mas percent recovery of Cu if you did not completely react the Mg in the reaction mi
Anarel [89]
The mass percentage would be reduced but not as much as if it were a complete reaction ヽ༼ຈل͜ຈ༽ノ︵┻━┻ mark brainliest please
6 0
3 years ago
Other questions:
  • Kelly is giving her friend directions to a nearby park. Which model would be most appropriate for her to use?
    7·2 answers
  • After our solar system began to form, dust and gas combined into small bodies that formed the planets. What are these small bodi
    5·2 answers
  • Why methanol is soluble in acetone
    10·1 answer
  • How many ml of ethyl alcohol are presented in 50 ml bottle of an 70%
    10·1 answer
  • What is the mass percent of each element in water
    15·1 answer
  • When Mrs. Green describes the physical properties of matter she said that physical properties often concern changes in state. On
    5·1 answer
  • Is anyone good at chemistry if so can someone help me please ?<br><br> (NO LINKS)
    12·1 answer
  • What is the volume in milliliters of 7.92 g of acetone?
    13·1 answer
  • A weak acid is titrated with 0.1236 M NaOH. From the titration curve you determine that the equivalence point occurs after exact
    5·1 answer
  • 2-8-6 refers to the proton configuration for sulfur.<br> True<br> Or False
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!