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STatiana [176]
3 years ago
13

Jenna is a scientist in a chemistry lab. Her experiment did not support her current theory. What should she do next?

Chemistry
2 answers:
dimaraw [331]3 years ago
6 0

Answer:

Jenna should: Verify the data by running the experiment several more times

Explanation:

Verifying your data can be done by running multiple trials to ensure that the results that come out was not due to other errors such as calculation mistakes, procedural errors, and the like. This will rule out other extraneous factors that could have unintentionally influenced the outcome of the experiment.

Dimas [21]3 years ago
3 0

Answer:

Verify the data by running the experiment several more times is the correct answer.

Explanation:

If Jenna wants to support her current theory, it is necessary that she checks every step of the procedure at least one more time. To make sure that she doesn't miss anything, it is necessary that she repeats the experiment one or several times in order to  verify that she is following the procedure as she should.

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Learn more about models: brainly.com/question/14281845

3 0
2 years ago
Which of the following is NOT an example of covalent bonding? * 2 points H20 NaF NH3 O2
Pachacha [2.7K]

Answer:

I THINK NH3

Explanation:

4 0
2 years ago
How do you view failure? Is failure the end, or is failure an important lesson and motivator?
Katyanochek1 [597]

Answer:

Failure is a lesson

Explanation:

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8 0
3 years ago
1) The densities of air at −85°C, 0°C, and 100°C are 1.877 g dm−3, 1.294 g dm−3, and 0.946 g dm−3, respectively. From these data
earnstyle [38]

Answer:

1) The absolute zero temperature is -272.74 °C

2) The absolute zero temperature is -269.91°C

Explanation:

1) The specific volume of air at the given temperatures are;

At -85°C, v =  1/(1.877) = 0.533 dm³/g, the pressure =

At 0°C, v = 1/1.294 ≈ 0.773 dm³/g

At 100°C, v = 1/0.946 ≈ 1.057 dm³/g

We therefore have;

v₁ = 0.533 T₁ = 188.15  K

v₂ = 0.773 T₂ = 273.15  K

v₃ = 1.057 T₃ = 373.15  K

The slope of the graph formed by the above data is therefore given as follows;

m = (1.057 - 0.533)/(373.15 - 188.5) = 0.00284 dm³/K

The equation is therefor;

v - 0.533 = 0.00284×(T - 188.15)

v = 0.00284×T - 0.534 + 0.533  = 0.00284×T - 0.001167

v =  0.00284×T - 0.001167

Therefore, when the temperature, at absolute 0, we have;

v = 0

Which gives;

0 =  0.00284×T - 0.001167

0.00284×T = 0.001167

T = 0.001167/0.00284 ≈ 0.411 K

Which is 0.411  -273.15 ≈ -272.74 °C

The absolute zero temperature is -272.74 °C

2) The given volume of the gas = 20.00 dm³ at 0°C and 1.000 atm

The slope of the volume temperature graph at constant pressure = 0.0741 dm³/(°C)

The temperature is converted to Kelvin temperature, in order to apply Charles law as follows;

0°C = 0 + 273.15 K = 273.15 K

Therefore, the equation of the graph can be presented as follows;

v - 20.00 = 0.0741 × (T - 273.15)

Which gives;

v = 0.0741·T - 0.0741 ×(273.15) + 20

v = 0.0741·T - 20.2404125 + 20

v = 0.0741·T - 0.240415

Therefore at absolute 0, v = 0, we have;

0 = 0.0741·T - 0.240415

0.0741·T = 0.240415

T = 0.240415/0.0741 = 3.2445 K

The temperature in degrees is therefore;

3.2445 K - 273.15 ≈ -269.91°C

The absolute zero temperature is therefore, -269.91°C

3 0
3 years ago
An atom has 5 protons and 7 neutrons. What is its mass number?
lisabon 2012 [21]
Mass number = protons + neutrons
mass number = 5 + 7
mass number = 12
3 0
3 years ago
Read 2 more answers
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