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STatiana [176]
3 years ago
13

Jenna is a scientist in a chemistry lab. Her experiment did not support her current theory. What should she do next?

Chemistry
2 answers:
dimaraw [331]3 years ago
6 0

Answer:

Jenna should: Verify the data by running the experiment several more times

Explanation:

Verifying your data can be done by running multiple trials to ensure that the results that come out was not due to other errors such as calculation mistakes, procedural errors, and the like. This will rule out other extraneous factors that could have unintentionally influenced the outcome of the experiment.

Dimas [21]3 years ago
3 0

Answer:

Verify the data by running the experiment several more times is the correct answer.

Explanation:

If Jenna wants to support her current theory, it is necessary that she checks every step of the procedure at least one more time. To make sure that she doesn't miss anything, it is necessary that she repeats the experiment one or several times in order to  verify that she is following the procedure as she should.

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Question 6 (1 point)
Mnenie [13.5K]

Answer:

The correct option is;

d 4400

Explanation:

The given parameters are;

The mass of the ice = 55 g

The Heat of Fusion = 80 cal/g

The Heat of Vaporization = 540 cal/g

The specific heat capacity of water = 1 cal/g

The heat required to melt a given mass of ice = The Heat of Fusion × The mass of the ice

The heat required to melt the 55 g mass of ice = 540 cal/g × 55 g = 29700 cal

The heat required to raise the temperature of a given mass ice (water) = The mass of the ice (water) × The specific heat capacity of the ice (water) × The temperature change

The heat required to raise the temperature of the ice from 0°C to 100°C = 55 × 1 × (100 - 0) = 5,500 cal

The heat required to vaporize a given mass of ice = The Heat of Vaporization × The mass of the ice

The heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal

The total heat required to boil 55 g of ice = 29700 cal + 5,500 cal + 4,400 cal = 39,600 cal

However, we note that the heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal.

The heat required to vaporize the 55 g mass of ice at 100°C = 4,400 cal

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