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STatiana [176]
3 years ago
13

Jenna is a scientist in a chemistry lab. Her experiment did not support her current theory. What should she do next?

Chemistry
2 answers:
dimaraw [331]3 years ago
6 0

Answer:

Jenna should: Verify the data by running the experiment several more times

Explanation:

Verifying your data can be done by running multiple trials to ensure that the results that come out was not due to other errors such as calculation mistakes, procedural errors, and the like. This will rule out other extraneous factors that could have unintentionally influenced the outcome of the experiment.

Dimas [21]3 years ago
3 0

Answer:

Verify the data by running the experiment several more times is the correct answer.

Explanation:

If Jenna wants to support her current theory, it is necessary that she checks every step of the procedure at least one more time. To make sure that she doesn't miss anything, it is necessary that she repeats the experiment one or several times in order to  verify that she is following the procedure as she should.

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A fire is an example of ________________ reaction, because heat is _____________ the system.
Over [174]

d. exothermic; leaving

  • Exothermic reaction is a reaction that produces heat in the reaction whereas the endothermic reaction is a reaction in which heat is required to be given in the reaction to produce product.
  • Fire is an exothermic reaction.
  • A fire is produced due to oxidation of the fuel in the form of liquid or gas.
  • A fire is an example of combustion.
  • In fire both heat and light are left from fire due to the oxidation of fuel.

Hence, option d. exothermic; leaving is the correct option.

Learn more about fire:

brainly.com/question/12761984

8 0
3 years ago
Read 2 more answers
A 25.0 L tank of nitrogen gas is at 25 oC and 2.05 atm . If the temperature stays at 25 oC and the volume is decreased to 14.5 L
NeTakaya

Answer:

\boxed {\boxed {\sf P_2 \approx 3.53 \ atm}}

Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

P_1V_1=P_2V_2

Now we can substitute any known values into the formula.

Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

25.0 \ L * 2.05 \ atm = P_2V_2

The volume is decreased to 14.5 liters, but the pressure is unknown.

25.0 \ L * 2.05 \ atm = P_2 * 14.5 \ L

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}=\frac{P_2 *14.5 \ L}{14.5 \ L}

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}= P_2

The units of liters cancel.

\frac {25.0  * 2.05 \ atm }{14.5 }=P_2

\frac {50.25\  atm }{14.5 }=P_2

3.53448276 \ atm = P_2

The original values of volume and pressure have 3 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 3.53448276

The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

3.53 \ atm \approx P_2

The new pressure is approximately <u>3.53 atmospheres.</u>

8 0
3 years ago
A solution that is able to dissolve additional solute is best described as
worty [1.4K]
<h2>Question:</h2>

  • A solution that is able to dissolve additional solute is best described as _____.

<h2>Answer:</h2>

<h2>D.) Unsaturated </h2>

  • <u>Unsaturated</u> means the substance is poured into the solvent that can be dissolved. It is a solution (with less solute than the saturated solution) that completely dissolves, leaving with no remaining substances.

<h2>For example:</h2>

  • If you were to pour olive oil into a glass of water, it will dissolve, so it is <u>unsaturated</u>.

_________

#LetsStudy

6 0
3 years ago
13. As heat is added to a lúguid that is boiling at constant
11Alexandr11 [23.1K]
Tbh I would pick A because the liquid* decreases. B doesn’t increase
6 0
3 years ago
Name the following compounds:
timama [110]
A) sodium fluoride
B) rubidium oxide
C) boron trichloride
D) dihydrogen selenide
E) tetraphosphate hexoxide
F) iodine trichloride
6 0
3 years ago
Read 2 more answers
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