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GenaCL600 [577]
3 years ago
14

What do small numbers of 12,22, and 11 stands for in C12H22O11​

Chemistry
1 answer:
Paladinen [302]3 years ago
4 0

Answer:

The number of each element in the molecule.

Explanation:

C₁₂H₂₂O₁₁ is one molecule, and it is made 3 elements carbon, hydrogen, and oxygen. There are 12 carbons, 22 hydrogens, and 11 oxygens. If these numbers were different, it would be a different molecule.

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Complete the passage about the properties of ionic compounds.
WITCHER [35]

Answer:

Following are the solution to the given question:

Explanation:

Due to the strong attachment among ions, it's indeed hard to break the covalent compounds in a combination. The ionic compounds, as they have a great melting point, become solid at room temperature, and may we say that the stronger between both the ions, as it is on a high point of fusion, is quite desirable.

3 0
2 years ago
Water's unique properties result from the fact that water
abruzzese [7]
Water molecules are polar and form hydrogen bonds.
8 0
3 years ago
Read 2 more answers
To learn how to calculate ion concentrations in an aqueous solution of a strong diprotic acid.
Kipish [7]

Answer:

The concentration of H⁺ ions is 0.0165 M.

Explanation:

Let's consider the dissociation of H₂SO₄. In the first step, H₂SO₄ acts as a strong acid, completely dissociating into HSO₄⁻ and H⁺. Therefore, the concentrations of these ions will be the <em>same</em> that the initial concentration of the acid.

           H₂SO₄ ⇒ HSO₄⁻ +    H⁺

Initial   0.010M        0            0

Final         0        0.010M   0.010M

Now, HSO₄⁻ is a weak acid that will dissociate partially to form H⁺ and SO₄²⁻.

HSO₄⁻ ⇄ H⁺ + SO₄²⁻

To find out the concentration of H⁺ from HSO₄⁻ we will use an ICE Chart. We recognize 3 stages: Initial, Change and Equilibrium, and complete each row with the concentration or change in concentration.

    HSO₄⁻ ⇄ H⁺ + SO₄²⁻

I   0.010        0        0

C     -x          +x      +x

E  0.010 -x    x         x

Ka2=0.012=\frac{[H^{+}].[SO_{4}^{2} ]}{H_{2}SO_{4}} =\frac{x^{2} }{0.010-x}

This quadratic equation has 2 solutions: x₁ = -0.018 and x₂ = 0.00649. Since concentrations cannot be negative, we choose x₂. Then, [H⁺] coming from HSO₄⁻ is 0.00649 M.

The total concentration of H⁺ is:

[H⁺] = 0.010 M + 0.00649 M = 0.0165 M

8 0
3 years ago
A sample of 0.8360 g of an unknown compound containing barium ions (Ba2+) is dissolved in water and treated with an excess of Na
adell [148]

Answer:

percentage by mass of Ba = 0.4583/0.8360  × 100 = 45.83 /0.8360 = 54.82%

Explanation:

The mass of Barium in the original compound is the same as the masss of barium in the precipitate BaSO4.

Ba²+

molar mass of BaSO4 = 137 + 32 + 16(4) = 137 + 32 + 64 = 233 g/ mol

since

137 grams of barium is in 233 g of BaSO4

? grams of barium is in 0.7794 g of BaSO4

cross multiply

grams of barium =  0.7794 × 137/233

grams of barium = 106.7778/233

grams of barium = 0.45827381974

grams of barium = 0.4583 grams

percentage  by mass of Barium in the original compound  =

mass of barium/ mass of the compound × 100

mass of barium =  0.4583 g

mass of compound = 0.8360 g

percentage by mass of Ba = 0.4583/0.8360  × 100 = 45.83 /0.8360 = 54.82%

6 0
3 years ago
Write the formula for the polyatomic ion in NaNO3. Express your answer as an ion.
Oliga [24]
NO₃⁻ is the polyatomic ion in this case.
4 0
3 years ago
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