What do small numbers of 12,22, and 11 stands for in C12H22O11
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Answer:
The concentration of H⁺ ions is 0.0165 M.
Explanation:
Let's consider the dissociation of H₂SO₄. In the first step, H₂SO₄ acts as a strong acid, completely dissociating into HSO₄⁻ and H⁺. Therefore, the concentrations of these ions will be the <em>same</em> that the initial concentration of the acid.
H₂SO₄ ⇒ HSO₄⁻ + H⁺
Initial 0.010M 0 0
Final 0 0.010M 0.010M
Now, HSO₄⁻ is a weak acid that will dissociate partially to form H⁺ and SO₄²⁻.
HSO₄⁻ ⇄ H⁺ + SO₄²⁻
To find out the concentration of H⁺ from HSO₄⁻ we will use an ICE Chart. We recognize 3 stages: Initial, Change and Equilibrium, and complete each row with the concentration or change in concentration.
HSO₄⁻ ⇄ H⁺ + SO₄²⁻
I 0.010 0 0
C -x +x +x
E 0.010 -x x x
This quadratic equation has 2 solutions: x₁ = -0.018 and x₂ = 0.00649. Since concentrations cannot be negative, we choose x₂. Then, [H⁺] coming from HSO₄⁻ is 0.00649 M.
The total concentration of H⁺ is:
[H⁺] = 0.010 M + 0.00649 M = 0.0165 M